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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 75 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹12100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  2. 2.What amount will ₹13200 grow to in 2 years at 15% per year compound interest (in ₹)?
  3. 3.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
  4. 4.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
  5. 5.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  6. 6.A town has 41500 people. The population grows by 5% every year. What will the population be after 1 year?
  7. 7.Find the compound interest on ₹20400 at 12% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹60000 at 5% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹55500 at 20% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹41300 at 25% per year for 1 year, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹8400 at 5% per year for 2 years (in ₹)?
  17. 17.Find the compound interest on ₹21600 at 5% per year for 2 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹28800 at 8% per year for 1 year, compounded every year (in ₹).
  19. 19.A town has 50600 people. The population grows by 4% every year. What will the population be after 1 year?
  20. 20.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹41200 at 25% per year for 1 year, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹43000 at 10% per year for 3 years, compounded every year (in ₹).
  23. 23.What amount will ₹47000 grow to in 3 years at 10% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹7800 at 10% per year for 1 year, compounded every year (in ₹).
  25. 25.A scooter is worth ₹45000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  26. 26.Find the compound interest on ₹8000 at 10% per year for 3 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹25600 at 5% per year for 2 years (in ₹)?
  28. 28.What amount will ₹13000 grow to in 1 year at 10% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹17000 at 15% per year for 1 year, compounded every year (in ₹).
  30. 30.A town has 2000 people. The population grows by 25% every year. What will the population be after 2 years?
  31. 31.What amount will ₹21100 grow to in 1 year at 15% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹54100 at 10% per year for 2 years (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  34. 34.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹12500 at 20% per year for 3 years, compounded every year (in ₹).
  36. 36.A scooter is worth ₹49700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  37. 37.A town has 21500 people. The population grows by 10% every year. What will the population be after 2 years?
  38. 38.A scooter is worth ₹2900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  39. 39.Find the compound interest on ₹26400 at 25% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹44800 at 25% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 11132
  2. 17457
  3. 27783
  4. 26
  5. 34295
  6. 43575
  7. 2448
  8. 3972
  9. 150
  10. 7566
  11. 2220
  12. 16668
  13. 10325
  14. 96
  15. 35075
  16. 21
  17. 2214
  18. 2304
  19. 52624
  20. 612
  21. 10300
  22. 14233
  23. 62557
  24. 780
  25. 40500
  26. 2648
  27. 64
  28. 14300
  29. 2550
  30. 3125
  31. 24265
  32. 541
  33. 12
  34. 40768
  35. 9100
  36. 43736
  37. 26015
  38. 2610
  39. 14850
  40. 25200

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