Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹12100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 2.What amount will ₹13200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 3.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
- 4.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
- 5.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 6.A town has 41500 people. The population grows by 5% every year. What will the population be after 1 year?
- 7.Find the compound interest on ₹20400 at 12% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
- 9.What is the difference between the compound interest and the simple interest on ₹60000 at 5% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹55500 at 20% per year for 2 years (in ₹)?
- 12.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹41300 at 25% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹8400 at 5% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹21600 at 5% per year for 2 years, compounded every year (in ₹).
- 18.Find the compound interest on ₹28800 at 8% per year for 1 year, compounded every year (in ₹).
- 19.A town has 50600 people. The population grows by 4% every year. What will the population be after 1 year?
- 20.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹41200 at 25% per year for 1 year, compounded every year (in ₹).
- 22.Find the compound interest on ₹43000 at 10% per year for 3 years, compounded every year (in ₹).
- 23.What amount will ₹47000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹7800 at 10% per year for 1 year, compounded every year (in ₹).
- 25.A scooter is worth ₹45000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 26.Find the compound interest on ₹8000 at 10% per year for 3 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹25600 at 5% per year for 2 years (in ₹)?
- 28.What amount will ₹13000 grow to in 1 year at 10% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹17000 at 15% per year for 1 year, compounded every year (in ₹).
- 30.A town has 2000 people. The population grows by 25% every year. What will the population be after 2 years?
- 31.What amount will ₹21100 grow to in 1 year at 15% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹54100 at 10% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
- 34.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 35.Find the compound interest on ₹12500 at 20% per year for 3 years, compounded every year (in ₹).
- 36.A scooter is worth ₹49700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 37.A town has 21500 people. The population grows by 10% every year. What will the population be after 2 years?
- 38.A scooter is worth ₹2900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 39.Find the compound interest on ₹26400 at 25% per year for 2 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹44800 at 25% per year for 2 years, compounded every year (in ₹).
Answer key
- 11132
- 17457
- 27783
- 26
- 34295
- 43575
- 2448
- 3972
- 150
- 7566
- 2220
- 16668
- 10325
- 96
- 35075
- 21
- 2214
- 2304
- 52624
- 612
- 10300
- 14233
- 62557
- 780
- 40500
- 2648
- 64
- 14300
- 2550
- 3125
- 24265
- 541
- 12
- 40768
- 9100
- 43736
- 26015
- 2610
- 14850
- 25200
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