Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 76 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹19600 at 15% per year for 2 years, compounded every year (in ₹).
2. 2.A town has 16000 people. The population grows by 12% every year. What will the population be after 1 year?
3. 3.What amount will ₹24500 grow to in 1 year at 10% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹27600 at 15% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹20400 at 20% per year for 2 years (in ₹)?
10. 10.What amount will ₹17000 grow to in 3 years at 10% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹7000 at 20% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹47000 at 20% per year for 3 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹6600 at 10% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹38600 at 25% per year for 1 year, compounded every year (in ₹).
15. 15.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
16. 16.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
17. 17.A scooter is worth ₹9600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹8400 at 20% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹24600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹21200 at 5% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹17700 at 20% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
23. 23.What amount will ₹49900 grow to in 1 year at 5% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹22500 at 10% per year for 2 years, compounded every year (in ₹).
25. 25.What amount will ₹56100 grow to in 1 year at 4% per year compound interest (in ₹)?
26. 26.A scooter is worth ₹19000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹7400 at 10% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹45000 at 25% per year for 1 year, compounded every year (in ₹).
30. 30.A town has 27500 people. The population grows by 8% every year. What will the population be after 2 years?
31. 31.A scooter is worth ₹7300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹20200 at 10% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹12500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
34. 34.What amount will ₹46500 grow to in 3 years at 20% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹55600 at 25% per year for 2 years (in ₹)?
36. 36.A town has 22800 people. The population grows by 25% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
38. 38.A town has 7000 people. The population grows by 20% every year. What will the population be after 3 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹6800 at 25% per year for 2 years (in ₹)?
40. 40.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?

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