Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 754 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹30000 at 5% per year for 1 year, compounded every year (in ₹).
2. 2.What amount will ₹35100 grow to in 1 year at 15% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹3600 at 25% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹32500 at 4% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹42100 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.A town has 7900 people. The population grows by 10% every year. What will the population be after 2 years?
8. 8.What is the difference between the compound interest and the simple interest on ₹39200 at 20% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹10000 at 15% per year for 2 years (in ₹)?
10. 10.What amount will ₹40500 grow to in 3 years at 20% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹38200 at 25% per year for 1 year, compounded every year (in ₹).
12. 12.A scooter is worth ₹5700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹26000 at 10% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹24400 at 15% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹24000 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹20300 at 20% per year for 2 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹44000 at 15% per year for 2 years (in ₹)?
18. 18.What amount will ₹29000 grow to in 3 years at 20% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹4400 at 25% per year for 2 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹5500 at 20% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹11900 grow to in 1 year at 10% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
23. 23.What amount will ₹22000 grow to in 3 years at 20% per year compound interest (in ₹)?
24. 24.A town has 6200 people. The population grows by 12% every year. What will the population be after 1 year?
25. 25.A scooter is worth ₹36100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
26. 26.Find the compound interest on ₹58100 at 10% per year for 1 year, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹12700 at 10% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹14400 at 5% per year for 2 years (in ₹)?
29. 29.A town has 43000 people. The population grows by 10% every year. What will the population be after 3 years?
30. 30.What amount will ₹12500 grow to in 2 years at 4% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).
32. 32.A town has 45000 people. The population grows by 4% every year. What will the population be after 2 years?
33. 33.Find the compound interest on ₹28000 at 10% per year for 3 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹39300 at 8% per year for 1 year, compounded every year (in ₹).
35. 35.A scooter is worth ₹26300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
36. 36.Find the compound interest on ₹5200 at 5% per year for 2 years, compounded every year (in ₹).
37. 37.What amount will ₹23600 grow to in 2 years at 25% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹39800 at 4% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹17100 at 10% per year for 2 years (in ₹)?

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