Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 757 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹12800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹4400 at 10% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹9600 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹59400 at 10% per year for 2 years (in ₹)?
5. 5.A town has 10400 people. The population grows by 25% every year. What will the population be after 2 years?
6. 6.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
7. 7.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
8. 8.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹47200 at 5% per year for 2 years (in ₹)?
10. 10.What amount will ₹12400 grow to in 1 year at 8% per year compound interest (in ₹)?
11. 11.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
12. 12.A town has 52900 people. The population grows by 10% every year. What will the population be after 1 year?
13. 13.What is the difference between the compound interest and the simple interest on ₹4900 at 20% per year for 2 years (in ₹)?
14. 14.A town has 4800 people. The population grows by 25% every year. What will the population be after 3 years?
15. 15.A town has 43900 people. The population grows by 8% every year. What will the population be after 1 year?
16. 16.A town has 36700 people. The population grows by 25% every year. What will the population be after 1 year?
17. 17.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
19. 19.A town has 2500 people. The population grows by 20% every year. What will the population be after 3 years?
20. 20.What amount will ₹40500 grow to in 3 years at 20% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹41600 at 15% per year for 2 years (in ₹)?
22. 22.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
23. 23.What is the difference between the compound interest and the simple interest on ₹2400 at 5% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹20000 at 20% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹50200 at 8% per year for 1 year, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?
27. 27.A town has 3600 people. The population grows by 15% every year. What will the population be after 1 year?
28. 28.Find the compound interest on ₹36000 at 5% per year for 1 year, compounded every year (in ₹).
29. 29.Find the compound interest on ₹17000 at 20% per year for 2 years, compounded every year (in ₹).
30. 30.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹5100 at 20% per year for 2 years (in ₹)?
32. 32.A town has 33700 people. The population grows by 12% every year. What will the population be after 1 year?
33. 33.What amount will ₹14600 grow to in 1 year at 25% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹35400 at 20% per year for 2 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹50800 grow to in 1 year at 4% per year compound interest (in ₹)?
37. 37.A scooter is worth ₹27500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
38. 38.A scooter is worth ₹12700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
39. 39.Find the compound interest on ₹46000 at 15% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹49200 grow to in 2 years at 20% per year compound interest (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets