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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 758 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹53200 at 20% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹26200 at 5% per year for 1 year, compounded every year (in ₹).
  3. 3.What amount will ₹53000 grow to in 3 years at 20% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  5. 5.A town has 56200 people. The population grows by 5% every year. What will the population be after 1 year?
  6. 6.What amount will ₹55400 grow to in 1 year at 20% per year compound interest (in ₹)?
  7. 7.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  8. 8.A town has 3200 people. The population grows by 25% every year. What will the population be after 2 years?
  9. 9.A scooter is worth ₹15100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  10. 10.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
  11. 11.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  12. 12.Find the compound interest on ₹54000 at 20% per year for 1 year, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹56600 at 4% per year for 1 year, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹14900 at 20% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹21000 at 10% per year for 3 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹57300 at 20% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
  19. 19.What amount will ₹36000 grow to in 3 years at 10% per year compound interest (in ₹)?
  20. 20.Find the compound interest on ₹17600 at 25% per year for 2 years, compounded every year (in ₹).
  21. 21.What amount will ₹59200 grow to in 2 years at 15% per year compound interest (in ₹)?
  22. 22.What amount will ₹53200 grow to in 2 years at 15% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  24. 24.What amount will ₹8000 grow to in 1 year at 12% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹35200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹23200 at 15% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹42800 at 5% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹5300 at 4% per year for 1 year, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹15400 at 8% per year for 1 year, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹42800 at 25% per year for 2 years, compounded every year (in ₹).
  31. 31.A scooter is worth ₹17400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  32. 32.Find the compound interest on ₹14000 at 12% per year for 1 year, compounded every year (in ₹).
  33. 33.What amount will ₹29700 grow to in 1 year at 8% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹41700 at 8% per year for 1 year, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹5400 at 25% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  38. 38.A scooter is worth ₹17500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  39. 39.A town has 11200 people. The population grows by 15% every year. What will the population be after 2 years?
  40. 40.Find the compound interest on ₹9600 at 5% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 2128
  2. 1310
  3. 91584
  4. 7566
  5. 59010
  6. 66480
  7. 3783
  8. 5000
  9. 12835
  10. 73002
  11. 41154
  12. 10800
  13. 2264
  14. 2980
  15. 6951
  16. 11460
  17. 5044
  18. 16668
  19. 47916
  20. 9900
  21. 78292
  22. 70357
  23. 8827
  24. 8960
  25. 33440
  26. 522
  27. 107
  28. 212
  29. 1232
  30. 24075
  31. 13050
  32. 1680
  33. 32076
  34. 3336
  35. 72
  36. 1350
  37. 16
  38. 14812
  39. 14812
  40. 984

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