Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹29000 at 25% per year for 1 year, compounded every year (in ₹).
- 2.What amount will ₹49600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 3.What amount will ₹46000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 4.Find the compound interest on ₹46800 at 5% per year for 2 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹39200 at 15% per year for 2 years, compounded every year (in ₹).
- 6.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 7.A scooter is worth ₹47400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 8.What amount will ₹6800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 9.A town has 9500 people. The population grows by 8% every year. What will the population be after 1 year?
- 10.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
- 11.What amount will ₹27600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 12.A town has 14700 people. The population grows by 10% every year. What will the population be after 1 year?
- 13.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
- 14.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹54400 at 25% per year for 2 years, compounded every year (in ₹).
- 18.What amount will ₹33400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 19.What amount will ₹60000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 20.What amount will ₹55300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 21.A town has 59200 people. The population grows by 15% every year. What will the population be after 2 years?
- 22.Find the compound interest on ₹34100 at 15% per year for 1 year, compounded every year (in ₹).
- 23.What amount will ₹2300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹15500 at 15% per year for 1 year, compounded every year (in ₹).
- 25.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 26.A scooter is worth ₹39400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 27.Find the compound interest on ₹57900 at 20% per year for 2 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 29.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 30.A town has 38800 people. The population grows by 5% every year. What will the population be after 2 years?
- 31.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹43300 at 12% per year for 1 year, compounded every year (in ₹).
- 35.Find the compound interest on ₹30700 at 10% per year for 1 year, compounded every year (in ₹).
- 36.What amount will ₹4800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 37.A scooter is worth ₹26300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 38.Find the compound interest on ₹25600 at 25% per year for 1 year, compounded every year (in ₹).
- 39.Find the compound interest on ₹29000 at 20% per year for 3 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
Answer key
- 7250
- 96875
- 61226
- 4797
- 12642
- 576
- 45030
- 8993
- 10260
- 432
- 36501
- 16170
- 2244
- 1261
- 720
- 128
- 30600
- 40414
- 64896
- 60830
- 78292
- 5115
- 2415
- 2325
- 6305
- 37430
- 25476
- 4167
- 28224
- 42777
- 48
- 612
- 8
- 5196
- 3070
- 9375
- 24985
- 6400
- 21112
- 4160
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