← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 763 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹57500 at 12% per year for 2 years, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹13100 at 20% per year for 1 year, compounded every year (in ₹).
  5. 5.A town has 51600 people. The population grows by 25% every year. What will the population be after 2 years?
  6. 6.Find the compound interest on ₹12000 at 15% per year for 1 year, compounded every year (in ₹).
  7. 7.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  8. 8.Find the compound interest on ₹33500 at 20% per year for 2 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  10. 10.What amount will ₹3200 grow to in 2 years at 25% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  12. 12.What amount will ₹36000 grow to in 3 years at 20% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  15. 15.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  16. 16.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹31200 at 15% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹48800 at 10% per year for 1 year, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹41100 at 10% per year for 2 years, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹18300 at 10% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹46800 at 25% per year for 2 years (in ₹)?
  23. 23.A town has 44400 people. The population grows by 5% every year. What will the population be after 2 years?
  24. 24.What amount will ₹15000 grow to in 2 years at 8% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹20800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹35600 at 5% per year for 2 years (in ₹)?
  27. 27.A town has 10800 people. The population grows by 25% every year. What will the population be after 1 year?
  28. 28.A town has 42500 people. The population grows by 20% every year. What will the population be after 3 years?
  29. 29.A scooter is worth ₹24100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹51300 at 10% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹15500 at 20% per year for 2 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹17000 at 4% per year for 1 year, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
  34. 34.A town has 11900 people. The population grows by 15% every year. What will the population be after 1 year?
  35. 35.What amount will ₹6300 grow to in 1 year at 12% per year compound interest (in ₹)?
  36. 36.A town has 25600 people. The population grows by 5% every year. What will the population be after 1 year?
  37. 37.Find the compound interest on ₹26400 at 25% per year for 1 year, compounded every year (in ₹).
  38. 38.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
  39. 39.Find the compound interest on ₹5400 at 25% per year for 1 year, compounded every year (in ₹).
  40. 40.What amount will ₹26700 grow to in 1 year at 4% per year compound interest (in ₹)?

Answer key

  1. 16668
  2. 1986
  3. 14628
  4. 2620
  5. 80625
  6. 1800
  7. 48668
  8. 14740
  9. 648
  10. 5000
  11. 6305
  12. 62208
  13. 5296
  14. 1261
  15. 29478
  16. 85169
  17. 702
  18. 9
  19. 4880
  20. 8631
  21. 183
  22. 2925
  23. 48951
  24. 17496
  25. 8775
  26. 89
  27. 13500
  28. 73440
  29. 15424
  30. 513
  31. 6820
  32. 680
  33. 6100
  34. 13685
  35. 7056
  36. 26880
  37. 6600
  38. 64827
  39. 1350
  40. 27768

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets