Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 764 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
2. 2.What amount will ₹20000 grow to in 2 years at 12% per year compound interest (in ₹)?
3. 3.A town has 33800 people. The population grows by 20% every year. What will the population be after 2 years?
4. 4.What amount will ₹11000 grow to in 1 year at 10% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
6. 6.What amount will ₹46000 grow to in 1 year at 25% per year compound interest (in ₹)?
7. 7.A town has 43000 people. The population grows by 12% every year. What will the population be after 1 year?
8. 8.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹10000 at 12% per year for 1 year, compounded every year (in ₹).
10. 10.A town has 31600 people. The population grows by 25% every year. What will the population be after 1 year?
11. 11.What is the difference between the compound interest and the simple interest on ₹50700 at 10% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹17500 at 20% per year for 3 years, compounded every year (in ₹).
13. 13.What amount will ₹21600 grow to in 1 year at 8% per year compound interest (in ₹)?
14. 14.A town has 47600 people. The population grows by 10% every year. What will the population be after 2 years?
15. 15.A scooter is worth ₹41600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
16. 16.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
17. 17.A scooter is worth ₹50000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
18. 18.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
19. 19.What amount will ₹43600 grow to in 1 year at 20% per year compound interest (in ₹)?
20. 20.A town has 49600 people. The population grows by 5% every year. What will the population be after 1 year?
21. 21.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹24400 at 15% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹46900 at 10% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹37200 grow to in 1 year at 10% per year compound interest (in ₹)?
25. 25.A town has 41700 people. The population grows by 25% every year. What will the population be after 1 year?
26. 26.Find the compound interest on ₹34500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
28. 28.What amount will ₹15600 grow to in 1 year at 10% per year compound interest (in ₹)?
29. 29.A town has 21600 people. The population grows by 8% every year. What will the population be after 1 year?
30. 30.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
31. 31.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
32. 32.What amount will ₹41800 grow to in 2 years at 20% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹45100 at 8% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹28300 at 8% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹48700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹58500 at 10% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹41600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
39. 39.Find the compound interest on ₹46100 at 12% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹30000 at 15% per year for 2 years, compounded every year (in ₹).

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