Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 769 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹28500 at 20% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
3. 3.A town has 43800 people. The population grows by 20% every year. What will the population be after 2 years?
4. 4.Find the compound interest on ₹26400 at 15% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹38200 at 10% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹3500 at 20% per year for 3 years, compounded every year (in ₹).
7. 7.A town has 18200 people. The population grows by 5% every year. What will the population be after 1 year?
8. 8.What is the difference between the compound interest and the simple interest on ₹10700 at 10% per year for 2 years (in ₹)?
9. 9.A town has 26500 people. The population grows by 20% every year. What will the population be after 3 years?
10. 10.What amount will ₹13900 grow to in 2 years at 10% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
12. 12.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹23000 at 5% per year for 1 year, compounded every year (in ₹).
14. 14.A scooter is worth ₹28200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
15. 15.A town has 10000 people. The population grows by 10% every year. What will the population be after 3 years?
16. 16.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹12800 at 25% per year for 3 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹42000 at 15% per year for 2 years (in ₹)?
20. 20.A town has 8500 people. The population grows by 10% every year. What will the population be after 1 year?
21. 21.Find the compound interest on ₹23500 at 20% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 38400 people. The population grows by 25% every year. What will the population be after 3 years?
23. 23.A scooter is worth ₹6000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹15600 at 5% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹19700 at 5% per year for 1 year, compounded every year (in ₹).
26. 26.A scooter is worth ₹40800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹29600 at 15% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹48000 grow to in 1 year at 8% per year compound interest (in ₹)?
30. 30.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
31. 31.What amount will ₹40000 grow to in 3 years at 25% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹14500 at 20% per year for 3 years, compounded every year (in ₹).
33. 33.A town has 3000 people. The population grows by 5% every year. What will the population be after 1 year?
34. 34.Find the compound interest on ₹16000 at 5% per year for 2 years, compounded every year (in ₹).
35. 35.A town has 20000 people. The population grows by 4% every year. What will the population be after 2 years?
36. 36.What amount will ₹8800 grow to in 1 year at 8% per year compound interest (in ₹)?
37. 37.A scooter is worth ₹56800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
38. 38.A town has 36700 people. The population grows by 25% every year. What will the population be after 1 year?
39. 39.What is the difference between the compound interest and the simple interest on ₹26400 at 5% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹38800 at 25% per year for 2 years (in ₹)?

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