Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 784 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
2. 2.A town has 50800 people. The population grows by 5% every year. What will the population be after 2 years?
3. 3.Find the compound interest on ₹58100 at 5% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
5. 5.What amount will ₹35600 grow to in 2 years at 5% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
7. 7.What amount will ₹58400 grow to in 2 years at 20% per year compound interest (in ₹)?
8. 8.What amount will ₹46000 grow to in 2 years at 25% per year compound interest (in ₹)?
9. 9.What amount will ₹25800 grow to in 1 year at 20% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹57600 at 25% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹27600 at 25% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹2200 at 12% per year for 1 year, compounded every year (in ₹).
13. 13.A town has 10900 people. The population grows by 20% every year. What will the population be after 1 year?
14. 14.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹41600 at 20% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹45000 at 20% per year for 3 years, compounded every year (in ₹).
17. 17.A town has 21000 people. The population grows by 4% every year. What will the population be after 1 year?
18. 18.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹28400 at 25% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
21. 21.A town has 31900 people. The population grows by 4% every year. What will the population be after 1 year?
22. 22.Find the compound interest on ₹33300 at 25% per year for 1 year, compounded every year (in ₹).
23. 23.Find the compound interest on ₹8400 at 25% per year for 2 years, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹55800 at 10% per year for 2 years (in ₹)?
26. 26.A town has 9400 people. The population grows by 12% every year. What will the population be after 1 year?
27. 27.Find the compound interest on ₹17000 at 10% per year for 3 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹17100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
29. 29.Find the compound interest on ₹11200 at 20% per year for 2 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹1600 at 25% per year for 3 years, compounded every year (in ₹).
32. 32.What amount will ₹43700 grow to in 1 year at 4% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹44000 at 15% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹19500 at 20% per year for 1 year, compounded every year (in ₹).
36. 36.A scooter is worth ₹31600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
37. 37.A town has 48000 people. The population grows by 10% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹10900 at 10% per year for 1 year, compounded every year (in ₹).
40. 40.A scooter is worth ₹25700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?

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