Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 79 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 54400 people. The population grows by 25% every year. What will the population be after 3 years?
2. 2.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
4. 4.A town has 22600 people. The population grows by 10% every year. What will the population be after 2 years?
5. 5.What amount will ₹11200 grow to in 2 years at 15% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹15200 at 12% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹36900 grow to in 2 years at 10% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹35600 at 20% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹33900 at 10% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹10000 at 15% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹34000 at 10% per year for 3 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹55600 grow to in 1 year at 25% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹11600 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹17600 at 15% per year for 2 years (in ₹)?
17. 17.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
18. 18.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹2400 at 15% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹31300 at 12% per year for 1 year, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹50300 at 10% per year for 2 years (in ₹)?
22. 22.What amount will ₹55500 grow to in 3 years at 20% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹25000 at 10% per year for 3 years, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹30600 at 20% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹42400 at 20% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹23500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹32300 at 8% per year for 1 year, compounded every year (in ₹).
29. 29.Find the compound interest on ₹7200 at 15% per year for 1 year, compounded every year (in ₹).
30. 30.A scooter is worth ₹21100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
31. 31.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
32. 32.What amount will ₹6200 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.A town has 26400 people. The population grows by 25% every year. What will the population be after 2 years?
34. 34.What amount will ₹6600 grow to in 1 year at 8% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹4900 at 5% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹16500 at 20% per year for 1 year, compounded every year (in ₹).
37. 37.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹52400 at 10% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹29000 at 10% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹33600 grow to in 3 years at 25% per year compound interest (in ₹)?

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