Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹16900 at 10% per year for 2 years (in ₹)?
- 2.Find the compound interest on ₹20400 at 25% per year for 1 year, compounded every year (in ₹).
- 3.What is the difference between the compound interest and the simple interest on ₹15600 at 5% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹38500 at 20% per year for 3 years, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 7.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
- 9.A scooter is worth ₹45200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹2200 at 20% per year for 2 years (in ₹)?
- 11.A town has 23000 people. The population grows by 10% every year. What will the population be after 3 years?
- 12.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 13.Find the compound interest on ₹37000 at 20% per year for 2 years, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹2700 at 10% per year for 2 years (in ₹)?
- 15.A scooter is worth ₹17600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 16.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 17.A town has 16000 people. The population grows by 25% every year. What will the population be after 2 years?
- 18.What is the difference between the compound interest and the simple interest on ₹49200 at 20% per year for 2 years (in ₹)?
- 19.What amount will ₹49600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 20.A scooter is worth ₹36300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 21.A scooter is worth ₹23000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 22.A town has 58800 people. The population grows by 5% every year. What will the population be after 2 years?
- 23.Find the compound interest on ₹15600 at 5% per year for 1 year, compounded every year (in ₹).
- 24.A town has 56300 people. The population grows by 10% every year. What will the population be after 2 years?
- 25.Find the compound interest on ₹21600 at 15% per year for 2 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹20200 at 10% per year for 2 years, compounded every year (in ₹).
- 27.A scooter is worth ₹23800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 28.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹46400 at 5% per year for 2 years (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
- 31.What amount will ₹12300 grow to in 1 year at 4% per year compound interest (in ₹)?
- 32.What amount will ₹11200 grow to in 2 years at 25% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹39600 at 15% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹26000 at 25% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
- 36.What amount will ₹7500 grow to in 2 years at 20% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹26200 at 15% per year for 1 year, compounded every year (in ₹).
- 38.What amount will ₹25000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 39.What amount will ₹51600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
Answer key
- 169
- 5100
- 39
- 28028
- 24
- 5044
- 32448
- 288
- 42940
- 88
- 30613
- 48
- 16280
- 27
- 15840
- 23328
- 25000
- 1968
- 96875
- 30855
- 16767
- 64827
- 780
- 68123
- 6966
- 4242
- 15232
- 13718
- 116
- 38
- 12792
- 17500
- 891
- 6500
- 60
- 10800
- 3930
- 27040
- 56889
- 180
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