Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 794 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹12300 at 20% per year for 1 year, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹20800 at 25% per year for 2 years (in ₹)?
4. 4.A town has 46500 people. The population grows by 10% every year. What will the population be after 2 years?
5. 5.Find the compound interest on ₹29200 at 25% per year for 2 years, compounded every year (in ₹).
6. 6.What amount will ₹25600 grow to in 2 years at 5% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
8. 8.A town has 4400 people. The population grows by 15% every year. What will the population be after 1 year?
9. 9.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
10. 10.A town has 6400 people. The population grows by 25% every year. What will the population be after 3 years?
11. 11.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
13. 13.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
14. 14.A scooter is worth ₹28800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
15. 15.Find the compound interest on ₹2300 at 12% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹20300 at 8% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹17500 grow to in 1 year at 20% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
19. 19.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
20. 20.A town has 8900 people. The population grows by 25% every year. What will the population be after 1 year?
21. 21.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?
22. 22.A scooter is worth ₹52000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹29700 at 10% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹22000 at 20% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹39000 at 20% per year for 1 year, compounded every year (in ₹).
26. 26.What amount will ₹26100 grow to in 1 year at 10% per year compound interest (in ₹)?
27. 27.A town has 22000 people. The population grows by 10% every year. What will the population be after 3 years?
28. 28.A scooter is worth ₹20000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
29. 29.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
30. 30.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹9000 grow to in 3 years at 10% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
33. 33.What amount will ₹17800 grow to in 1 year at 12% per year compound interest (in ₹)?
34. 34.A town has 52100 people. The population grows by 10% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹42400 at 20% per year for 2 years, compounded every year (in ₹).
36. 36.A town has 30000 people. The population grows by 12% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹11300 at 8% per year for 1 year, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹46000 at 20% per year for 2 years (in ₹)?
40. 40.A town has 13700 people. The population grows by 10% every year. What will the population be after 2 years?

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