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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 795 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹48500 at 20% per year for 2 years (in ₹)?
  2. 2.What amount will ₹32600 grow to in 1 year at 4% per year compound interest (in ₹)?
  3. 3.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
  4. 4.A town has 50800 people. The population grows by 10% every year. What will the population be after 2 years?
  5. 5.What amount will ₹13300 grow to in 1 year at 5% per year compound interest (in ₹)?
  6. 6.A scooter is worth ₹5200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  7. 7.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
  8. 8.What is the difference between the compound interest and the simple interest on ₹23100 at 10% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹13300 at 20% per year for 2 years (in ₹)?
  10. 10.What amount will ₹28800 grow to in 3 years at 25% per year compound interest (in ₹)?
  11. 11.A town has 17600 people. The population grows by 8% every year. What will the population be after 1 year?
  12. 12.What is the difference between the compound interest and the simple interest on ₹58900 at 10% per year for 2 years (in ₹)?
  13. 13.A scooter is worth ₹53500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  14. 14.A town has 29000 people. The population grows by 15% every year. What will the population be after 1 year?
  15. 15.Find the compound interest on ₹5300 at 15% per year for 1 year, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹55400 at 20% per year for 2 years (in ₹)?
  17. 17.What amount will ₹27900 grow to in 1 year at 8% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹52000 at 10% per year for 2 years, compounded every year (in ₹).
  19. 19.What amount will ₹49000 grow to in 3 years at 20% per year compound interest (in ₹)?
  20. 20.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
  21. 21.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹8800 at 10% per year for 2 years (in ₹)?
  23. 23.What amount will ₹56900 grow to in 2 years at 10% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
  25. 25.A town has 56700 people. The population grows by 4% every year. What will the population be after 1 year?
  26. 26.What is the difference between the compound interest and the simple interest on ₹32000 at 5% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹22800 at 20% per year for 2 years (in ₹)?
  28. 28.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  29. 29.What amount will ₹52800 grow to in 2 years at 10% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
  31. 31.What amount will ₹10000 grow to in 3 years at 20% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  33. 33.A town has 51200 people. The population grows by 25% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹31200 at 20% per year for 2 years, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹15200 at 10% per year for 2 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  38. 38.What amount will ₹22800 grow to in 2 years at 5% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹28700 at 8% per year for 1 year, compounded every year (in ₹).
  40. 40.A scooter is worth ₹49000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?

Answer key

  1. 1940
  2. 33904
  3. 10816
  4. 61468
  5. 13965
  6. 3757
  7. 12167
  8. 231
  9. 532
  10. 56250
  11. 19008
  12. 589
  13. 43335
  14. 33350
  15. 795
  16. 2216
  17. 30132
  18. 10920
  19. 84672
  20. 12544
  21. 32625
  22. 88
  23. 68849
  24. 10812
  25. 58968
  26. 80
  27. 912
  28. 27648
  29. 63888
  30. 6360
  31. 17280
  32. 12501
  33. 80000
  34. 13728
  35. 56
  36. 3192
  37. 5044
  38. 25137
  39. 2296
  40. 35721

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