Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹48500 at 20% per year for 2 years (in ₹)?
- 2.What amount will ₹32600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 3.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 4.A town has 50800 people. The population grows by 10% every year. What will the population be after 2 years?
- 5.What amount will ₹13300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 6.A scooter is worth ₹5200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 7.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
- 8.What is the difference between the compound interest and the simple interest on ₹23100 at 10% per year for 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹13300 at 20% per year for 2 years (in ₹)?
- 10.What amount will ₹28800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 11.A town has 17600 people. The population grows by 8% every year. What will the population be after 1 year?
- 12.What is the difference between the compound interest and the simple interest on ₹58900 at 10% per year for 2 years (in ₹)?
- 13.A scooter is worth ₹53500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 14.A town has 29000 people. The population grows by 15% every year. What will the population be after 1 year?
- 15.Find the compound interest on ₹5300 at 15% per year for 1 year, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹55400 at 20% per year for 2 years (in ₹)?
- 17.What amount will ₹27900 grow to in 1 year at 8% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹52000 at 10% per year for 2 years, compounded every year (in ₹).
- 19.What amount will ₹49000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 20.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹8800 at 10% per year for 2 years (in ₹)?
- 23.What amount will ₹56900 grow to in 2 years at 10% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
- 25.A town has 56700 people. The population grows by 4% every year. What will the population be after 1 year?
- 26.What is the difference between the compound interest and the simple interest on ₹32000 at 5% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹22800 at 20% per year for 2 years (in ₹)?
- 28.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 29.What amount will ₹52800 grow to in 2 years at 10% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
- 31.What amount will ₹10000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 32.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 33.A town has 51200 people. The population grows by 25% every year. What will the population be after 2 years?
- 34.Find the compound interest on ₹31200 at 20% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹15200 at 10% per year for 2 years, compounded every year (in ₹).
- 37.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 38.What amount will ₹22800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹28700 at 8% per year for 1 year, compounded every year (in ₹).
- 40.A scooter is worth ₹49000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
Answer key
- 1940
- 33904
- 10816
- 61468
- 13965
- 3757
- 12167
- 231
- 532
- 56250
- 19008
- 589
- 43335
- 33350
- 795
- 2216
- 30132
- 10920
- 84672
- 12544
- 32625
- 88
- 68849
- 10812
- 58968
- 80
- 912
- 27648
- 63888
- 6360
- 17280
- 12501
- 80000
- 13728
- 56
- 3192
- 5044
- 25137
- 2296
- 35721
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