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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 803 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹34300 grow to in 2 years at 10% per year compound interest (in ₹)?
  2. 2.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹32500 at 12% per year for 1 year, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹55800 at 20% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹19700 at 20% per year for 2 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹20000 at 12% per year for 2 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹44300 at 4% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹18000 grow to in 2 years at 15% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹12000 at 5% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹45200 at 25% per year for 2 years (in ₹)?
  12. 12.What amount will ₹47800 grow to in 1 year at 15% per year compound interest (in ₹)?
  13. 13.A town has 2400 people. The population grows by 20% every year. What will the population be after 1 year?
  14. 14.What amount will ₹48500 grow to in 3 years at 20% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹57000 at 10% per year for 2 years, compounded every year (in ₹).
  16. 16.What amount will ₹38800 grow to in 1 year at 25% per year compound interest (in ₹)?
  17. 17.What amount will ₹14900 grow to in 2 years at 10% per year compound interest (in ₹)?
  18. 18.A town has 9800 people. The population grows by 4% every year. What will the population be after 1 year?
  19. 19.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹7200 at 20% per year for 2 years, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
  23. 23.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
  24. 24.A scooter is worth ₹44500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  25. 25.What amount will ₹48000 grow to in 2 years at 25% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹34200 at 10% per year for 2 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹35600 at 5% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹41800 at 10% per year for 2 years (in ₹)?
  30. 30.What amount will ₹18000 grow to in 3 years at 20% per year compound interest (in ₹)?
  31. 31.A scooter is worth ₹53000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  32. 32.A town has 12700 people. The population grows by 10% every year. What will the population be after 2 years?
  33. 33.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹28900 at 20% per year for 2 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹43200 at 25% per year for 1 year, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹58800 at 25% per year for 2 years (in ₹)?
  37. 37.What amount will ₹4800 grow to in 2 years at 15% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹4500 at 4% per year for 1 year, compounded every year (in ₹).
  39. 39.A town has 8700 people. The population grows by 10% every year. What will the population be after 1 year?
  40. 40.Find the compound interest on ₹32700 at 10% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 41503
  2. 4913
  3. 68
  4. 3900
  5. 2232
  6. 8668
  7. 5088
  8. 1772
  9. 23805
  10. 1230
  11. 2825
  12. 54970
  13. 2880
  14. 83808
  15. 11970
  16. 48500
  17. 18029
  18. 10192
  19. 12501
  20. 1071
  21. 3168
  22. 96
  23. 81250
  24. 35600
  25. 75000
  26. 60
  27. 342
  28. 89
  29. 418
  30. 31104
  31. 38637
  32. 15367
  33. 272
  34. 12716
  35. 10800
  36. 3675
  37. 6348
  38. 180
  39. 9570
  40. 3270

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