Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 36700 people. The population grows by 8% every year. What will the population be after 1 year?
- 2.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹34100 at 20% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
- 5.A town has 58400 people. The population grows by 10% every year. What will the population be after 1 year?
- 6.Find the compound interest on ₹30000 at 12% per year for 1 year, compounded every year (in ₹).
- 7.What amount will ₹16400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 8.A town has 21400 people. The population grows by 12% every year. What will the population be after 1 year?
- 9.What is the difference between the compound interest and the simple interest on ₹2000 at 15% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹38000 at 5% per year for 2 years, compounded every year (in ₹).
- 11.A scooter is worth ₹57500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 12.Find the compound interest on ₹45500 at 20% per year for 1 year, compounded every year (in ₹).
- 13.Find the compound interest on ₹41600 at 5% per year for 1 year, compounded every year (in ₹).
- 14.Find the compound interest on ₹42000 at 20% per year for 3 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
- 16.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 17.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 18.A scooter is worth ₹15000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 19.Find the compound interest on ₹4800 at 20% per year for 1 year, compounded every year (in ₹).
- 20.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹51600 at 5% per year for 2 years, compounded every year (in ₹).
- 22.Find the compound interest on ₹12400 at 15% per year for 1 year, compounded every year (in ₹).
- 23.Find the compound interest on ₹8500 at 10% per year for 2 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
- 26.What amount will ₹17600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 27.A scooter is worth ₹7700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 28.A scooter is worth ₹22500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 29.A scooter is worth ₹9200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 30.A town has 30100 people. The population grows by 10% every year. What will the population be after 2 years?
- 31.A town has 19100 people. The population grows by 15% every year. What will the population be after 1 year?
- 32.Find the compound interest on ₹17500 at 20% per year for 1 year, compounded every year (in ₹).
- 33.Find the compound interest on ₹44900 at 12% per year for 1 year, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹46000 at 10% per year for 3 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹53300 at 8% per year for 1 year, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹45900 at 10% per year for 2 years (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
- 39.What amount will ₹29200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹58600 at 8% per year for 1 year, compounded every year (in ₹).
Answer key
- 39636
- 192
- 1364
- 12
- 64240
- 3600
- 25625
- 23968
- 45
- 3895
- 52992
- 9100
- 2080
- 30576
- 272
- 28224
- 48013
- 13824
- 960
- 180
- 5289
- 1860
- 1785
- 3060
- 72
- 18304
- 6237
- 20736
- 8303
- 36421
- 21965
- 3500
- 5388
- 96
- 15226
- 4264
- 459
- 360
- 35040
- 4688
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