Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 2.What amount will ₹60000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹47600 at 25% per year for 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹45800 at 20% per year for 2 years (in ₹)?
- 6.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
- 7.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹10000 at 25% per year for 2 years, compounded every year (in ₹).
- 9.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 10.What amount will ₹34800 grow to in 1 year at 25% per year compound interest (in ₹)?
- 11.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 12.What amount will ₹32500 grow to in 1 year at 5% per year compound interest (in ₹)?
- 13.A scooter is worth ₹13300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 14.Find the compound interest on ₹4700 at 20% per year for 1 year, compounded every year (in ₹).
- 15.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹3500 at 20% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹17600 at 20% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹15000 at 4% per year for 1 year, compounded every year (in ₹).
- 19.Find the compound interest on ₹20200 at 25% per year for 1 year, compounded every year (in ₹).
- 20.Find the compound interest on ₹2400 at 15% per year for 2 years, compounded every year (in ₹).
- 21.A scooter is worth ₹44800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 22.Find the compound interest on ₹48000 at 10% per year for 3 years, compounded every year (in ₹).
- 23.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 24.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 25.Find the compound interest on ₹45900 at 12% per year for 1 year, compounded every year (in ₹).
- 26.A town has 16500 people. The population grows by 20% every year. What will the population be after 2 years?
- 27.Find the compound interest on ₹18500 at 20% per year for 3 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹16400 at 5% per year for 2 years, compounded every year (in ₹).
- 29.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹35900 at 10% per year for 2 years (in ₹)?
- 31.What amount will ₹53400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 32.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹6100 at 10% per year for 2 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹32600 at 20% per year for 2 years, compounded every year (in ₹).
- 35.A town has 6700 people. The population grows by 5% every year. What will the population be after 1 year?
- 36.What is the difference between the compound interest and the simple interest on ₹16400 at 10% per year for 2 years (in ₹)?
- 37.Find the compound interest on ₹7700 at 10% per year for 2 years, compounded every year (in ₹).
- 38.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 39.What amount will ₹40500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
Answer key
- 13718
- 64896
- 48
- 2975
- 1832
- 24334
- 60835
- 5625
- 24334
- 43500
- 34295
- 34125
- 10773
- 940
- 6996
- 140
- 704
- 600
- 5050
- 774
- 41216
- 15888
- 18928
- 21600
- 5508
- 23760
- 13468
- 1681
- 14580
- 359
- 56070
- 37044
- 1281
- 14344
- 7035
- 164
- 1617
- 29478
- 69984
- 67
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets