Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 826 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹4100 at 12% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹27000 at 20% per year for 2 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹11200 at 20% per year for 2 years (in ₹)?
8. 8.What amount will ₹27000 grow to in 3 years at 10% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹29600 at 20% per year for 2 years, compounded every year (in ₹).
11. 11.What amount will ₹57000 grow to in 1 year at 15% per year compound interest (in ₹)?
12. 12.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
13. 13.Find the compound interest on ₹14500 at 25% per year for 1 year, compounded every year (in ₹).
14. 14.A scooter is worth ₹7500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
15. 15.Find the compound interest on ₹54400 at 25% per year for 2 years, compounded every year (in ₹).
16. 16.A scooter is worth ₹22400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹8000 at 25% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹41900 at 25% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹56000 at 5% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹8900 at 20% per year for 2 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
24. 24.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹15800 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
27. 27.What amount will ₹43100 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
29. 29.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
30. 30.A town has 26500 people. The population grows by 20% every year. What will the population be after 3 years?
31. 31.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
32. 32.What amount will ₹42600 grow to in 1 year at 15% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹37000 at 20% per year for 3 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹24400 at 15% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 53000 people. The population grows by 10% every year. What will the population be after 3 years?
38. 38.Find the compound interest on ₹17600 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.A town has 27200 people. The population grows by 20% every year. What will the population be after 1 year?
40. 40.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?

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