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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 827 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  2. 2.Find the compound interest on ₹11600 at 5% per year for 2 years, compounded every year (in ₹).
  3. 3.What is the difference between the compound interest and the simple interest on ₹52400 at 5% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹2000 at 5% per year for 2 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹47500 at 4% per year for 2 years, compounded every year (in ₹).
  6. 6.A town has 44500 people. The population grows by 10% every year. What will the population be after 2 years?
  7. 7.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹27800 at 20% per year for 2 years (in ₹)?
  9. 9.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  10. 10.What amount will ₹23400 grow to in 1 year at 15% per year compound interest (in ₹)?
  11. 11.A town has 36900 people. The population grows by 20% every year. What will the population be after 2 years?
  12. 12.What amount will ₹7600 grow to in 2 years at 5% per year compound interest (in ₹)?
  13. 13.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  14. 14.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹29700 at 25% per year for 1 year, compounded every year (in ₹).
  16. 16.A scooter is worth ₹25500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹58500 at 10% per year for 1 year, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
  20. 20.What amount will ₹44800 grow to in 2 years at 5% per year compound interest (in ₹)?
  21. 21.What amount will ₹19500 grow to in 1 year at 12% per year compound interest (in ₹)?
  22. 22.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  23. 23.A scooter is worth ₹19700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  24. 24.A scooter is worth ₹28500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  25. 25.Find the compound interest on ₹12800 at 20% per year for 2 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
  29. 29.What is the difference between the compound interest and the simple interest on ₹23600 at 10% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹41200 at 10% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  32. 32.A town has 33500 people. The population grows by 4% every year. What will the population be after 1 year?
  33. 33.What amount will ₹45000 grow to in 2 years at 4% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹12800 at 25% per year for 1 year, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹42200 at 20% per year for 1 year, compounded every year (in ₹).
  36. 36.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹53200 at 25% per year for 2 years (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹21200 at 15% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹38800 at 25% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹52400 at 10% per year for 2 years (in ₹)?

Answer key

  1. 10580
  2. 1189
  3. 131
  4. 205
  5. 3876
  6. 53845
  7. 2522
  8. 1112
  9. 1261
  10. 26910
  11. 53136
  12. 8379
  13. 41154
  14. 37044
  15. 7425
  16. 16320
  17. 684
  18. 5850
  19. 47275
  20. 49392
  21. 21840
  22. 9826
  23. 17730
  24. 18240
  25. 5632
  26. 272
  27. 8
  28. 8904
  29. 236
  30. 412
  31. 540
  32. 34840
  33. 48672
  34. 3200
  35. 8440
  36. 39930
  37. 3325
  38. 477
  39. 2425
  40. 524

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