Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 830 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
2. 2.A town has 54900 people. The population grows by 12% every year. What will the population be after 1 year?
3. 3.A scooter is worth ₹22000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
4. 4.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
5. 5.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
6. 6.What amount will ₹58200 grow to in 1 year at 4% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹47400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
8. 8.A town has 60000 people. The population grows by 12% every year. What will the population be after 2 years?
9. 9.What amount will ₹17600 grow to in 2 years at 5% per year compound interest (in ₹)?
10. 10.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
11. 11.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
14. 14.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹30600 at 10% per year for 2 years, compounded every year (in ₹).
16. 16.A town has 31000 people. The population grows by 10% every year. What will the population be after 3 years?
17. 17.Find the compound interest on ₹49000 at 10% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹18600 at 10% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹4100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
21. 21.A town has 57500 people. The population grows by 20% every year. What will the population be after 3 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹54400 at 5% per year for 2 years (in ₹)?
23. 23.A town has 49900 people. The population grows by 10% every year. What will the population be after 1 year?
24. 24.What amount will ₹8700 grow to in 1 year at 8% per year compound interest (in ₹)?
25. 25.A town has 14300 people. The population grows by 4% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹39200 at 10% per year for 2 years (in ₹)?
27. 27.What amount will ₹54600 grow to in 1 year at 12% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹18000 at 20% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹30000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
31. 31.A town has 7600 people. The population grows by 12% every year. What will the population be after 1 year?
32. 32.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹4500 at 20% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹33900 at 10% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
36. 36.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹12900 at 10% per year for 2 years (in ₹)?
38. 38.What amount will ₹22800 grow to in 1 year at 20% per year compound interest (in ₹)?
39. 39.A town has 11000 people. The population grows by 20% every year. What will the population be after 2 years?
40. 40.Find the compound interest on ₹47000 at 10% per year for 3 years, compounded every year (in ₹).

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