Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹34100 at 10% per year for 2 years (in ₹)?
- 3.What amount will ₹26000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 4.A scooter is worth ₹14500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹45600 at 15% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹21000 at 20% per year for 2 years, compounded every year (in ₹).
- 8.Find the compound interest on ₹4000 at 15% per year for 1 year, compounded every year (in ₹).
- 9.A scooter is worth ₹2500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 10.A scooter is worth ₹44800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 11.Find the compound interest on ₹55500 at 20% per year for 1 year, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹34800 at 15% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 14.What amount will ₹16200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹29200 at 25% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹46800 at 5% per year for 2 years, compounded every year (in ₹).
- 19.A scooter is worth ₹10000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 20.Find the compound interest on ₹57600 at 25% per year for 3 years, compounded every year (in ₹).
- 21.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹14400 at 15% per year for 2 years (in ₹)?
- 23.A town has 40000 people. The population grows by 12% every year. What will the population be after 1 year?
- 24.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 25.A town has 5700 people. The population grows by 10% every year. What will the population be after 2 years?
- 26.Find the compound interest on ₹18900 at 10% per year for 2 years, compounded every year (in ₹).
- 27.A town has 16200 people. The population grows by 12% every year. What will the population be after 1 year?
- 28.What is the difference between the compound interest and the simple interest on ₹19900 at 10% per year for 2 years (in ₹)?
- 29.What amount will ₹15000 grow to in 1 year at 25% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹32800 at 15% per year for 2 years (in ₹)?
- 31.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹5500 at 20% per year for 3 years, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹31600 at 15% per year for 2 years (in ₹)?
- 35.A scooter is worth ₹4800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 36.Find the compound interest on ₹22900 at 4% per year for 1 year, compounded every year (in ₹).
- 37.What amount will ₹5000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 38.A town has 37000 people. The population grows by 10% every year. What will the population be after 1 year?
- 39.What amount will ₹14400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 40.What amount will ₹50500 grow to in 3 years at 20% per year compound interest (in ₹)?
Answer key
- 4576
- 341
- 44928
- 13050
- 1026
- 1272
- 9240
- 600
- 2116
- 36288
- 11100
- 783
- 720
- 17010
- 3060
- 1664
- 1825
- 4797
- 7290
- 54900
- 68
- 324
- 44800
- 6859
- 6897
- 3969
- 18144
- 199
- 18750
- 738
- 21875
- 224
- 4004
- 711
- 3840
- 916
- 5750
- 40700
- 22500
- 87264
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