Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹51000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 2.Find the compound interest on ₹54300 at 20% per year for 2 years, compounded every year (in ₹).
- 3.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹12800 at 5% per year for 2 years (in ₹)?
- 5.A scooter is worth ₹47400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 6.A town has 7500 people. The population grows by 8% every year. What will the population be after 2 years?
- 7.What is the difference between the compound interest and the simple interest on ₹58400 at 5% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹34000 at 25% per year for 2 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹35000 at 8% per year for 1 year, compounded every year (in ₹).
- 10.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
- 11.What amount will ₹47100 grow to in 2 years at 10% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹10100 at 10% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹9300 at 10% per year for 2 years (in ₹)?
- 14.Find the compound interest on ₹56000 at 15% per year for 1 year, compounded every year (in ₹).
- 15.A scooter is worth ₹29200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 16.What amount will ₹11600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 17.Find the compound interest on ₹5900 at 10% per year for 1 year, compounded every year (in ₹).
- 18.Find the compound interest on ₹39500 at 8% per year for 1 year, compounded every year (in ₹).
- 19.A town has 36800 people. The population grows by 25% every year. What will the population be after 3 years?
- 20.What is the difference between the compound interest and the simple interest on ₹28500 at 20% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹19900 at 20% per year for 2 years (in ₹)?
- 22.A town has 12600 people. The population grows by 8% every year. What will the population be after 1 year?
- 23.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹37200 at 15% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹44400 at 10% per year for 2 years, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹22400 at 25% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹23000 at 20% per year for 3 years, compounded every year (in ₹).
- 29.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
- 30.What amount will ₹54100 grow to in 2 years at 10% per year compound interest (in ₹)?
- 31.A town has 35200 people. The population grows by 25% every year. What will the population be after 3 years?
- 32.Find the compound interest on ₹58200 at 5% per year for 1 year, compounded every year (in ₹).
- 33.What amount will ₹15600 grow to in 1 year at 25% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹53600 at 5% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹51000 at 20% per year for 3 years, compounded every year (in ₹).
- 36.A scooter is worth ₹3500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 37.What amount will ₹24000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 38.A scooter is worth ₹47200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 39.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 40.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
Answer key
- 48450
- 23892
- 44
- 32
- 42660
- 8748
- 146
- 19125
- 2800
- 6100
- 56991
- 101
- 93
- 8400
- 27740
- 12789
- 590
- 3160
- 71875
- 1140
- 796
- 13608
- 85169
- 837
- 9324
- 1400
- 8
- 16744
- 64
- 65461
- 68750
- 2910
- 19500
- 134
- 37128
- 2975
- 41472
- 42598
- 14739
- 1261
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