Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹24000 at 10% per year for 1 year, compounded every year (in ₹).
- 2.A scooter is worth ₹24500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 3.A town has 20400 people. The population grows by 5% every year. What will the population be after 2 years?
- 4.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 5.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 6.What amount will ₹5500 grow to in 2 years at 10% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹48400 at 25% per year for 2 years (in ₹)?
- 8.What amount will ₹45600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 9.A scooter is worth ₹35600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 10.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹11400 at 10% per year for 1 year, compounded every year (in ₹).
- 13.A scooter is worth ₹36000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹26600 at 20% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹21400 at 12% per year for 1 year, compounded every year (in ₹).
- 19.What amount will ₹58100 grow to in 2 years at 20% per year compound interest (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹11200 at 25% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
- 22.Find the compound interest on ₹23400 at 5% per year for 1 year, compounded every year (in ₹).
- 23.Find the compound interest on ₹21600 at 25% per year for 2 years, compounded every year (in ₹).
- 24.What amount will ₹24100 grow to in 1 year at 5% per year compound interest (in ₹)?
- 25.A scooter is worth ₹35000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 26.A town has 18900 people. The population grows by 4% every year. What will the population be after 1 year?
- 27.A town has 32500 people. The population grows by 15% every year. What will the population be after 1 year?
- 28.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 29.A scooter is worth ₹59700. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 30.What amount will ₹50200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 31.What amount will ₹4200 grow to in 1 year at 8% per year compound interest (in ₹)?
- 32.Find the compound interest on ₹16000 at 15% per year for 2 years, compounded every year (in ₹).
- 33.What amount will ₹18400 grow to in 1 year at 25% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹12800 at 5% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹16700 at 25% per year for 1 year, compounded every year (in ₹).
- 36.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 37.Find the compound interest on ₹40400 at 25% per year for 2 years, compounded every year (in ₹).
- 38.What amount will ₹8000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹35600 at 15% per year for 2 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹14900 at 10% per year for 2 years, compounded every year (in ₹).
Answer key
- 2400
- 12544
- 22491
- 28224
- 34295
- 6655
- 3025
- 50274
- 32129
- 55566
- 20835
- 1140
- 31680
- 1064
- 6996
- 8
- 576
- 2568
- 83664
- 700
- 324
- 1170
- 12150
- 25305
- 32256
- 19656
- 37375
- 19652
- 38208
- 60240
- 4536
- 5160
- 23000
- 32
- 4175
- 4167
- 22725
- 10648
- 11481
- 3129
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