← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 840 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹44800 at 25% per year for 3 years, compounded every year (in ₹).
  2. 2.A scooter is worth ₹40000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  3. 3.A town has 20500 people. The population grows by 10% every year. What will the population be after 1 year?
  4. 4.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
  5. 5.What amount will ₹53000 grow to in 3 years at 10% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹28400 at 25% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹23600 at 25% per year for 2 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹39100 at 4% per year for 1 year, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹16000 at 5% per year for 2 years, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹51400 at 25% per year for 1 year, compounded every year (in ₹).
  12. 12.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  13. 13.Find the compound interest on ₹4400 at 5% per year for 2 years, compounded every year (in ₹).
  14. 14.What amount will ₹45600 grow to in 2 years at 15% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  16. 16.What amount will ₹18000 grow to in 3 years at 10% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹7200 at 15% per year for 2 years (in ₹)?
  19. 19.A town has 4100 people. The population grows by 5% every year. What will the population be after 1 year?
  20. 20.A town has 22400 people. The population grows by 25% every year. What will the population be after 2 years?
  21. 21.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
  22. 22.Find the compound interest on ₹8500 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.Find the compound interest on ₹58100 at 5% per year for 1 year, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹43600 at 10% per year for 1 year, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹6400 at 15% per year for 2 years (in ₹)?
  26. 26.What amount will ₹4800 grow to in 1 year at 10% per year compound interest (in ₹)?
  27. 27.What amount will ₹24000 grow to in 2 years at 15% per year compound interest (in ₹)?
  28. 28.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹40000 at 25% per year for 2 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹42000 at 10% per year for 2 years, compounded every year (in ₹).
  32. 32.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
  33. 33.A scooter is worth ₹7900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹2400 at 20% per year for 2 years (in ₹)?
  35. 35.What amount will ₹18800 grow to in 1 year at 5% per year compound interest (in ₹)?
  36. 36.A scooter is worth ₹3800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹20400 at 5% per year for 2 years (in ₹)?
  38. 38.What amount will ₹26500 grow to in 1 year at 10% per year compound interest (in ₹)?
  39. 39.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  40. 40.What amount will ₹53100 grow to in 1 year at 8% per year compound interest (in ₹)?

Answer key

  1. 42700
  2. 36864
  3. 22550
  4. 4452
  5. 70543
  6. 1775
  7. 13275
  8. 1564
  9. 10812
  10. 1640
  11. 12850
  12. 19652
  13. 451
  14. 60306
  15. 6305
  16. 23958
  17. 6656
  18. 162
  19. 4305
  20. 35000
  21. 43904
  22. 850
  23. 2905
  24. 4360
  25. 144
  26. 5280
  27. 31740
  28. 34992
  29. 13356
  30. 22500
  31. 8820
  32. 25000
  33. 7110
  34. 96
  35. 19740
  36. 2432
  37. 51
  38. 29150
  39. 34295
  40. 57348

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets