Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 845 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 52800 people. The population grows by 25% every year. What will the population be after 1 year?
2. 2.What amount will ₹10500 grow to in 1 year at 5% per year compound interest (in ₹)?
3. 3.What amount will ₹39200 grow to in 2 years at 5% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹57400 at 10% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹34100 at 10% per year for 2 years, compounded every year (in ₹).
6. 6.A scooter is worth ₹18000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
7. 7.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
8. 8.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹32800 at 10% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹13900 at 20% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
14. 14.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
16. 16.A town has 44000 people. The population grows by 15% every year. What will the population be after 2 years?
17. 17.Find the compound interest on ₹20400 at 25% per year for 2 years, compounded every year (in ₹).
18. 18.A town has 42500 people. The population grows by 10% every year. What will the population be after 1 year?
19. 19.What amount will ₹4000 grow to in 3 years at 20% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹16800 at 10% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹52800 at 25% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹20000 at 10% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹54700 at 20% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹28200 at 20% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹34700 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹24900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
27. 27.A town has 48900 people. The population grows by 12% every year. What will the population be after 1 year?
28. 28.A town has 56200 people. The population grows by 5% every year. What will the population be after 1 year?
29. 29.A scooter is worth ₹42300. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹9200 at 15% per year for 2 years (in ₹)?
31. 31.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
32. 32.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹11300 at 10% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹50800 at 5% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
36. 36.What amount will ₹48100 grow to in 1 year at 8% per year compound interest (in ₹)?
37. 37.What amount will ₹35000 grow to in 1 year at 12% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹39600 at 12% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹27600 at 5% per year for 2 years (in ₹)?

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