Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹51200 at 25% per year for 3 years, compounded every year (in ₹).
- 2.A scooter is worth ₹12000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹17200 at 15% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹19500 at 20% per year for 3 years, compounded every year (in ₹).
- 5.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹2000 at 20% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹35000 at 10% per year for 3 years, compounded every year (in ₹).
- 9.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
- 10.Find the compound interest on ₹21600 at 25% per year for 2 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹48400 at 25% per year for 2 years, compounded every year (in ₹).
- 12.What amount will ₹40800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 13.What amount will ₹7200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹15000 at 8% per year for 2 years, compounded every year (in ₹).
- 15.A scooter is worth ₹2300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 16.A town has 38900 people. The population grows by 20% every year. What will the population be after 1 year?
- 17.Find the compound interest on ₹47100 at 8% per year for 1 year, compounded every year (in ₹).
- 18.What amount will ₹51200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
- 20.What amount will ₹56800 grow to in 1 year at 4% per year compound interest (in ₹)?
- 21.What amount will ₹56400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹17600 at 5% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹18000 at 8% per year for 1 year, compounded every year (in ₹).
- 24.Find the compound interest on ₹3400 at 8% per year for 1 year, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹40400 at 25% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹2800 at 25% per year for 2 years, compounded every year (in ₹).
- 27.A scooter is worth ₹56300. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 28.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 29.What amount will ₹48500 grow to in 1 year at 12% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
- 31.What amount will ₹9700 grow to in 1 year at 4% per year compound interest (in ₹)?
- 32.What amount will ₹14400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 33.A scooter is worth ₹11000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 34.Find the compound interest on ₹34400 at 8% per year for 1 year, compounded every year (in ₹).
- 35.Find the compound interest on ₹40000 at 25% per year for 2 years, compounded every year (in ₹).
- 36.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 37.A scooter is worth ₹56700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 38.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
- 39.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹10800 at 15% per year for 2 years, compounded every year (in ₹).
Answer key
- 48800
- 10830
- 387
- 14196
- 59584
- 1836
- 80
- 11585
- 12167
- 12150
- 27225
- 53958
- 7920
- 2496
- 2185
- 46680
- 3768
- 61440
- 112
- 59072
- 62181
- 44
- 1440
- 272
- 2525
- 1575
- 54048
- 43740
- 54320
- 6100
- 10088
- 19044
- 8019
- 2752
- 22500
- 18750
- 51030
- 10675
- 13725
- 3483
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