Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹17700 at 12% per year for 1 year, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
- 3.What amount will ₹12000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 4.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
- 5.A scooter is worth ₹17500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 6.Find the compound interest on ₹25800 at 5% per year for 1 year, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹58200 at 20% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹12600 at 10% per year for 2 years (in ₹)?
- 9.What amount will ₹15500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 10.A town has 44900 people. The population grows by 8% every year. What will the population be after 1 year?
- 11.A town has 47700 people. The population grows by 5% every year. What will the population be after 1 year?
- 12.What amount will ₹21000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 13.A scooter is worth ₹54700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 14.What amount will ₹47000 grow to in 1 year at 25% per year compound interest (in ₹)?
- 15.What amount will ₹15000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 16.A town has 52500 people. The population grows by 8% every year. What will the population be after 2 years?
- 17.What is the difference between the compound interest and the simple interest on ₹47900 at 10% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹35600 at 15% per year for 2 years, compounded every year (in ₹).
- 19.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
- 20.A town has 24900 people. The population grows by 20% every year. What will the population be after 1 year?
- 21.What is the difference between the compound interest and the simple interest on ₹56100 at 10% per year for 2 years (in ₹)?
- 22.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
- 23.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 24.A scooter is worth ₹29900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 25.Find the compound interest on ₹18200 at 4% per year for 1 year, compounded every year (in ₹).
- 26.Find the compound interest on ₹4400 at 15% per year for 2 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹33700 at 20% per year for 1 year, compounded every year (in ₹).
- 28.A scooter is worth ₹22500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 29.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 30.A scooter is worth ₹29700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 31.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹30000 at 20% per year for 1 year, compounded every year (in ₹).
- 34.What amount will ₹23500 grow to in 1 year at 15% per year compound interest (in ₹)?
- 35.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹24500 at 20% per year for 1 year, compounded every year (in ₹).
- 37.Find the compound interest on ₹46100 at 4% per year for 1 year, compounded every year (in ₹).
- 38.A scooter is worth ₹28200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 39.Find the compound interest on ₹9500 at 4% per year for 1 year, compounded every year (in ₹).
- 40.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
Answer key
- 2124
- 180
- 15870
- 26244
- 16128
- 1290
- 2328
- 126
- 26784
- 48492
- 50085
- 36288
- 50324
- 58750
- 25920
- 61236
- 479
- 11481
- 6996
- 29880
- 561
- 2544
- 12501
- 22425
- 728
- 1419
- 6740
- 19125
- 64827
- 26730
- 416
- 2448
- 6000
- 27025
- 48668
- 4900
- 1844
- 22842
- 380
- 47275
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