Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 47900 people. The population grows by 15% every year. What will the population be after 1 year?
- 2.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 3.A town has 55000 people. The population grows by 20% every year. What will the population be after 2 years?
- 4.Find the compound interest on ₹33300 at 4% per year for 1 year, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹16300 at 20% per year for 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹11900 at 20% per year for 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹2000 at 25% per year for 2 years (in ₹)?
- 8.A scooter is worth ₹55500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 9.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 10.A town has 48400 people. The population grows by 5% every year. What will the population be after 2 years?
- 11.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹58500 at 10% per year for 2 years (in ₹)?
- 13.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 14.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 15.What amount will ₹52600 grow to in 1 year at 8% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹32900 at 20% per year for 2 years (in ₹)?
- 17.A scooter is worth ₹7500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 18.What amount will ₹2100 grow to in 2 years at 10% per year compound interest (in ₹)?
- 19.Find the compound interest on ₹23000 at 25% per year for 1 year, compounded every year (in ₹).
- 20.Find the compound interest on ₹32500 at 4% per year for 2 years, compounded every year (in ₹).
- 21.Find the compound interest on ₹19000 at 12% per year for 1 year, compounded every year (in ₹).
- 22.A town has 9200 people. The population grows by 25% every year. What will the population be after 2 years?
- 23.A scooter is worth ₹44500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 24.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹59100 at 20% per year for 1 year, compounded every year (in ₹).
- 28.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹42800 at 25% per year for 2 years, compounded every year (in ₹).
- 30.A town has 45600 people. The population grows by 25% every year. What will the population be after 1 year?
- 31.Find the compound interest on ₹32000 at 10% per year for 3 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹12500 at 20% per year for 2 years, compounded every year (in ₹).
- 33.What amount will ₹10200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹10300 at 20% per year for 2 years, compounded every year (in ₹).
- 35.Find the compound interest on ₹48500 at 20% per year for 2 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹8100 at 20% per year for 1 year, compounded every year (in ₹).
- 37.Find the compound interest on ₹34800 at 8% per year for 1 year, compounded every year (in ₹).
- 38.Find the compound interest on ₹24600 at 8% per year for 1 year, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
- 40.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
Answer key
- 55085
- 8748
- 79200
- 1332
- 652
- 476
- 125
- 28416
- 12501
- 53361
- 54571
- 585
- 3783
- 85169
- 56808
- 1316
- 6912
- 2541
- 5750
- 2652
- 2280
- 14375
- 28480
- 12167
- 68
- 112
- 11820
- 9261
- 24075
- 57000
- 10592
- 5500
- 12342
- 4532
- 21340
- 1620
- 2784
- 1968
- 368
- 64827
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