Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 852 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹36400 at 15% per year for 2 years (in ₹)?
2. 2.A town has 29400 people. The population grows by 5% every year. What will the population be after 1 year?
3. 3.What is the difference between the compound interest and the simple interest on ₹13200 at 5% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹58200 at 10% per year for 2 years (in ₹)?
6. 6.A scooter is worth ₹24400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
7. 7.Find the compound interest on ₹35700 at 8% per year for 1 year, compounded every year (in ₹).
8. 8.Find the compound interest on ₹28600 at 5% per year for 1 year, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹45000 at 8% per year for 1 year, compounded every year (in ₹).
11. 11.A town has 10500 people. The population grows by 20% every year. What will the population be after 3 years?
12. 12.What amount will ₹59400 grow to in 1 year at 12% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹14100 at 15% per year for 1 year, compounded every year (in ₹).
14. 14.What amount will ₹30400 grow to in 1 year at 5% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹50800 at 5% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹14700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
17. 17.Find the compound interest on ₹41000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
19. 19.A town has 47500 people. The population grows by 20% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹59600 at 5% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹37300 grow to in 2 years at 10% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
23. 23.A town has 18000 people. The population grows by 25% every year. What will the population be after 2 years?
24. 24.A town has 27500 people. The population grows by 4% every year. What will the population be after 2 years?
25. 25.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
26. 26.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
28. 28.What amount will ₹46200 grow to in 2 years at 20% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
31. 31.What amount will ₹8300 grow to in 1 year at 20% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹31600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹17200 at 15% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 28400 people. The population grows by 15% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
36. 36.A town has 58200 people. The population grows by 5% every year. What will the population be after 1 year?
37. 37.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
38. 38.A scooter is worth ₹48500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
39. 39.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
40. 40.A scooter is worth ₹31900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?

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