Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 2.What amount will ₹55200 grow to in 1 year at 8% per year compound interest (in ₹)?
- 3.What amount will ₹49300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 4.What amount will ₹51200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 5.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 6.What amount will ₹24600 grow to in 1 year at 10% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹16300 at 10% per year for 2 years (in ₹)?
- 8.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
- 9.A scooter is worth ₹47000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 10.What amount will ₹44800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹35700 at 20% per year for 1 year, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹27100 at 20% per year for 2 years (in ₹)?
- 14.What amount will ₹59200 grow to in 2 years at 25% per year compound interest (in ₹)?
- 15.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
- 16.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹8800 at 20% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹42400 at 15% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
- 20.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 21.A town has 36400 people. The population grows by 15% every year. What will the population be after 2 years?
- 22.Find the compound interest on ₹33000 at 12% per year for 1 year, compounded every year (in ₹).
- 23.A scooter is worth ₹6400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
- 25.What amount will ₹43600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 26.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
- 27.What is the difference between the compound interest and the simple interest on ₹49600 at 10% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
- 29.What amount will ₹18000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 30.What amount will ₹57400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 31.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 32.What amount will ₹37600 grow to in 1 year at 10% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹24800 at 20% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹51200 at 25% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
- 36.What amount will ₹42500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹5200 at 15% per year for 2 years, compounded every year (in ₹).
- 38.Find the compound interest on ₹3600 at 20% per year for 1 year, compounded every year (in ₹).
- 39.A town has 33000 people. The population grows by 4% every year. What will the population be after 1 year?
- 40.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
Answer key
- 25002
- 59616
- 53244
- 56448
- 2522
- 27060
- 163
- 60835
- 42300
- 87500
- 5044
- 7140
- 1084
- 92500
- 64827
- 4160
- 352
- 954
- 13356
- 18522
- 48139
- 3960
- 2700
- 30
- 45344
- 12167
- 496
- 44225
- 20700
- 60270
- 61236
- 41360
- 992
- 12800
- 256
- 53312
- 1677
- 720
- 34320
- 42592
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