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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 873 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹30000 grow to in 3 years at 20% per year compound interest (in ₹)?
  2. 2.What amount will ₹46000 grow to in 3 years at 10% per year compound interest (in ₹)?
  3. 3.A town has 31200 people. The population grows by 5% every year. What will the population be after 2 years?
  4. 4.A town has 55700 people. The population grows by 8% every year. What will the population be after 1 year?
  5. 5.A town has 3900 people. The population grows by 12% every year. What will the population be after 1 year?
  6. 6.A town has 45000 people. The population grows by 4% every year. What will the population be after 2 years?
  7. 7.Find the compound interest on ₹11200 at 5% per year for 2 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹48100 at 10% per year for 1 year, compounded every year (in ₹).
  9. 9.A town has 48100 people. The population grows by 15% every year. What will the population be after 1 year?
  10. 10.What amount will ₹28100 grow to in 1 year at 20% per year compound interest (in ₹)?
  11. 11.What amount will ₹14400 grow to in 2 years at 5% per year compound interest (in ₹)?
  12. 12.A scooter is worth ₹3200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  13. 13.What amount will ₹52800 grow to in 2 years at 5% per year compound interest (in ₹)?
  14. 14.What amount will ₹35200 grow to in 2 years at 10% per year compound interest (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹57600 at 15% per year for 2 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
  17. 17.A scooter is worth ₹37700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  18. 18.Find the compound interest on ₹19300 at 12% per year for 1 year, compounded every year (in ₹).
  19. 19.A town has 3600 people. The population grows by 25% every year. What will the population be after 1 year?
  20. 20.A scooter is worth ₹4800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  21. 21.Find the compound interest on ₹56800 at 10% per year for 1 year, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  25. 25.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
  26. 26.Find the compound interest on ₹20900 at 15% per year for 1 year, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹13600 at 25% per year for 2 years (in ₹)?
  28. 28.What amount will ₹51000 grow to in 3 years at 10% per year compound interest (in ₹)?
  29. 29.What amount will ₹15000 grow to in 1 year at 10% per year compound interest (in ₹)?
  30. 30.What amount will ₹7700 grow to in 1 year at 8% per year compound interest (in ₹)?
  31. 31.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  32. 32.What amount will ₹47600 grow to in 1 year at 10% per year compound interest (in ₹)?
  33. 33.What amount will ₹50500 grow to in 1 year at 10% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹50000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  35. 35.A town has 4300 people. The population grows by 25% every year. What will the population be after 1 year?
  36. 36.What amount will ₹8700 grow to in 1 year at 12% per year compound interest (in ₹)?
  37. 37.What amount will ₹51600 grow to in 2 years at 10% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹3500 at 20% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹34800 at 15% per year for 1 year, compounded every year (in ₹).
  40. 40.A town has 17500 people. The population grows by 20% every year. What will the population be after 1 year?

Answer key

  1. 51840
  2. 61226
  3. 34398
  4. 60156
  5. 4368
  6. 48672
  7. 1148
  8. 4810
  9. 55315
  10. 33720
  11. 15876
  12. 1350
  13. 58212
  14. 42592
  15. 1296
  16. 108
  17. 30537
  18. 2316
  19. 4500
  20. 3468
  21. 5680
  22. 8334
  23. 36
  24. 25002
  25. 68992
  26. 3135
  27. 850
  28. 67881
  29. 16500
  30. 8316
  31. 64827
  32. 52360
  33. 55550
  34. 25600
  35. 5375
  36. 9744
  37. 62436
  38. 140
  39. 5220
  40. 21000

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