Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 887 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹35600 at 4% per year for 1 year, compounded every year (in ₹).
3. 3.A scooter is worth ₹44200. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
4. 4.A town has 2000 people. The population grows by 15% every year. What will the population be after 2 years?
5. 5.What is the difference between the compound interest and the simple interest on ₹13600 at 25% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹56900 grow to in 1 year at 12% per year compound interest (in ₹)?
8. 8.A town has 5700 people. The population grows by 4% every year. What will the population be after 1 year?
9. 9.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹37200 at 25% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹7400 at 20% per year for 1 year, compounded every year (in ₹).
12. 12.What amount will ₹41900 grow to in 1 year at 10% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹6400 at 15% per year for 2 years (in ₹)?
14. 14.A town has 47800 people. The population grows by 4% every year. What will the population be after 1 year?
15. 15.What is the difference between the compound interest and the simple interest on ₹17700 at 10% per year for 2 years (in ₹)?
16. 16.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
17. 17.A town has 53000 people. The population grows by 10% every year. What will the population be after 3 years?
18. 18.Find the compound interest on ₹25300 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
20. 20.A scooter is worth ₹40500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
21. 21.A scooter is worth ₹52000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
22. 22.Find the compound interest on ₹40000 at 10% per year for 3 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹18200 at 5% per year for 1 year, compounded every year (in ₹).
24. 24.A scooter is worth ₹40400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
25. 25.A scooter is worth ₹60000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
26. 26.What amount will ₹9600 grow to in 2 years at 5% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
28. 28.What amount will ₹51800 grow to in 1 year at 15% per year compound interest (in ₹)?
29. 29.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹20400 at 8% per year for 1 year, compounded every year (in ₹).
32. 32.A town has 5200 people. The population grows by 15% every year. What will the population be after 1 year?
33. 33.A scooter is worth ₹14300. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
34. 34.Find the compound interest on ₹10000 at 5% per year for 1 year, compounded every year (in ₹).
35. 35.What amount will ₹8600 grow to in 2 years at 10% per year compound interest (in ₹)?
36. 36.A town has 27500 people. The population grows by 4% every year. What will the population be after 2 years?
37. 37.What amount will ₹59200 grow to in 3 years at 25% per year compound interest (in ₹)?
38. 38.A town has 15000 people. The population grows by 10% every year. What will the population be after 3 years?
39. 39.Find the compound interest on ₹49200 at 15% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?

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