Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 894 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹39300. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
2. 2.Find the compound interest on ₹56000 at 5% per year for 2 years, compounded every year (in ₹).
3. 3.A town has 12000 people. The population grows by 10% every year. What will the population be after 3 years?
4. 4.Find the compound interest on ₹47600 at 25% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹59200 at 25% per year for 2 years (in ₹)?
7. 7.What amount will ₹17300 grow to in 1 year at 10% per year compound interest (in ₹)?
8. 8.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
9. 9.What amount will ₹27600 grow to in 2 years at 5% per year compound interest (in ₹)?
10. 10.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹37600 at 5% per year for 1 year, compounded every year (in ₹).
13. 13.What amount will ₹36800 grow to in 2 years at 15% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹49200 at 15% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹49500 grow to in 3 years at 20% per year compound interest (in ₹)?
17. 17.A town has 37200 people. The population grows by 5% every year. What will the population be after 2 years?
18. 18.A scooter is worth ₹31000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
19. 19.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹19200 at 25% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹18000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
23. 23.What amount will ₹38800 grow to in 2 years at 25% per year compound interest (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹22800 at 5% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹27000 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹31200 at 8% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹39000 grow to in 3 years at 20% per year compound interest (in ₹)?
28. 28.A town has 48000 people. The population grows by 10% every year. What will the population be after 3 years?
29. 29.What is the difference between the compound interest and the simple interest on ₹47600 at 5% per year for 2 years (in ₹)?
30. 30.What amount will ₹35400 grow to in 1 year at 25% per year compound interest (in ₹)?
31. 31.What amount will ₹54500 grow to in 1 year at 5% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
33. 33.Find the compound interest on ₹38700 at 20% per year for 2 years, compounded every year (in ₹).
34. 34.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹45200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
37. 37.Find the compound interest on ₹4300 at 8% per year for 1 year, compounded every year (in ₹).
38. 38.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
39. 39.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
40. 40.What is the difference between the compound interest and the simple interest on ₹46100 at 10% per year for 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets