Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 895 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹30500 grow to in 3 years at 20% per year compound interest (in ₹)?
2. 2.What amount will ₹31600 grow to in 2 years at 25% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹55800 at 20% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
6. 6.What amount will ₹2600 grow to in 1 year at 4% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹57900 at 10% per year for 1 year, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹15600 at 10% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
10. 10.A town has 20300 people. The population grows by 25% every year. What will the population be after 1 year?
11. 11.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
12. 12.A town has 45200 people. The population grows by 25% every year. What will the population be after 2 years?
13. 13.Find the compound interest on ₹22700 at 10% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
15. 15.What amount will ₹31900 grow to in 1 year at 8% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
17. 17.A town has 41700 people. The population grows by 12% every year. What will the population be after 1 year?
18. 18.What is the difference between the compound interest and the simple interest on ₹7200 at 10% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹50400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
20. 20.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
21. 21.A town has 17600 people. The population grows by 20% every year. What will the population be after 2 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
23. 23.What amount will ₹60000 grow to in 3 years at 10% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹12800 at 15% per year for 2 years, compounded every year (in ₹).
25. 25.What amount will ₹42000 grow to in 2 years at 5% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
27. 27.A town has 6400 people. The population grows by 25% every year. What will the population be after 3 years?
28. 28.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹23600 at 20% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹21400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
31. 31.A town has 15400 people. The population grows by 10% every year. What will the population be after 2 years?
32. 32.What amount will ₹49600 grow to in 1 year at 25% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹43500 at 10% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹49500 at 20% per year for 3 years, compounded every year (in ₹).
35. 35.What amount will ₹4900 grow to in 1 year at 10% per year compound interest (in ₹)?
36. 36.A town has 17200 people. The population grows by 25% every year. What will the population be after 2 years?
37. 37.A town has 53600 people. The population grows by 15% every year. What will the population be after 2 years?
38. 38.A town has 46800 people. The population grows by 25% every year. What will the population be after 1 year?
39. 39.Find the compound interest on ₹49600 at 8% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?

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