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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 9 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹46200 at 20% per year for 2 years (in ₹)?
  2. 2.A scooter is worth ₹9900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  3. 3.What amount will ₹58800 grow to in 2 years at 20% per year compound interest (in ₹)?
  4. 4.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
  5. 5.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹58400 at 5% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹44000 at 10% per year for 3 years, compounded every year (in ₹).
  8. 8.A scooter is worth ₹5000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹31200 at 25% per year for 2 years (in ₹)?
  10. 10.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹26400 at 25% per year for 2 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹45200 at 5% per year for 2 years (in ₹)?
  13. 13.A scooter is worth ₹14000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  14. 14.What amount will ₹2000 grow to in 3 years at 10% per year compound interest (in ₹)?
  15. 15.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  16. 16.A scooter is worth ₹30800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  17. 17.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹18800 at 25% per year for 2 years (in ₹)?
  19. 19.A town has 26600 people. The population grows by 10% every year. What will the population be after 1 year?
  20. 20.Find the compound interest on ₹35900 at 12% per year for 1 year, compounded every year (in ₹).
  21. 21.What amount will ₹52100 grow to in 1 year at 8% per year compound interest (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹59200 at 20% per year for 2 years (in ₹)?
  23. 23.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹47500 at 12% per year for 1 year, compounded every year (in ₹).
  26. 26.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
  27. 27.Find the compound interest on ₹30400 at 5% per year for 2 years, compounded every year (in ₹).
  28. 28.A town has 5500 people. The population grows by 20% every year. What will the population be after 3 years?
  29. 29.A town has 27800 people. The population grows by 10% every year. What will the population be after 1 year?
  30. 30.Find the compound interest on ₹55200 at 8% per year for 1 year, compounded every year (in ₹).
  31. 31.A scooter is worth ₹38000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  32. 32.What amount will ₹50800 grow to in 1 year at 4% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹2900 at 10% per year for 1 year, compounded every year (in ₹).
  34. 34.What amount will ₹10100 grow to in 1 year at 8% per year compound interest (in ₹)?
  35. 35.A scooter is worth ₹55200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  36. 36.Find the compound interest on ₹28100 at 12% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹16900 at 4% per year for 1 year, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹6800 at 20% per year for 2 years (in ₹)?
  40. 40.A town has 5300 people. The population grows by 20% every year. What will the population be after 1 year?

Answer key

  1. 1848
  2. 9405
  3. 84672
  4. 25000
  5. 2025
  6. 2920
  7. 14564
  8. 4750
  9. 1950
  10. 2704
  11. 14850
  12. 113
  13. 12635
  14. 2662
  15. 27783
  16. 23100
  17. 29478
  18. 1175
  19. 29260
  20. 4308
  21. 56268
  22. 2368
  23. 46305
  24. 304
  25. 5700
  26. 27783
  27. 3116
  28. 9504
  29. 30580
  30. 4416
  31. 19456
  32. 52832
  33. 290
  34. 10908
  35. 52440
  36. 3372
  37. 1075
  38. 676
  39. 272
  40. 6360

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