Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹46200 at 20% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹9900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 3.What amount will ₹58800 grow to in 2 years at 20% per year compound interest (in ₹)?
- 4.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
- 5.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹58400 at 5% per year for 1 year, compounded every year (in ₹).
- 7.Find the compound interest on ₹44000 at 10% per year for 3 years, compounded every year (in ₹).
- 8.A scooter is worth ₹5000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹31200 at 25% per year for 2 years (in ₹)?
- 10.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹26400 at 25% per year for 2 years, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹45200 at 5% per year for 2 years (in ₹)?
- 13.A scooter is worth ₹14000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 14.What amount will ₹2000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 15.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 16.A scooter is worth ₹30800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 17.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹18800 at 25% per year for 2 years (in ₹)?
- 19.A town has 26600 people. The population grows by 10% every year. What will the population be after 1 year?
- 20.Find the compound interest on ₹35900 at 12% per year for 1 year, compounded every year (in ₹).
- 21.What amount will ₹52100 grow to in 1 year at 8% per year compound interest (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹59200 at 20% per year for 2 years (in ₹)?
- 23.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹47500 at 12% per year for 1 year, compounded every year (in ₹).
- 26.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
- 27.Find the compound interest on ₹30400 at 5% per year for 2 years, compounded every year (in ₹).
- 28.A town has 5500 people. The population grows by 20% every year. What will the population be after 3 years?
- 29.A town has 27800 people. The population grows by 10% every year. What will the population be after 1 year?
- 30.Find the compound interest on ₹55200 at 8% per year for 1 year, compounded every year (in ₹).
- 31.A scooter is worth ₹38000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 32.What amount will ₹50800 grow to in 1 year at 4% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹2900 at 10% per year for 1 year, compounded every year (in ₹).
- 34.What amount will ₹10100 grow to in 1 year at 8% per year compound interest (in ₹)?
- 35.A scooter is worth ₹55200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 36.Find the compound interest on ₹28100 at 12% per year for 1 year, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹16900 at 4% per year for 1 year, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹6800 at 20% per year for 2 years (in ₹)?
- 40.A town has 5300 people. The population grows by 20% every year. What will the population be after 1 year?
Answer key
- 1848
- 9405
- 84672
- 25000
- 2025
- 2920
- 14564
- 4750
- 1950
- 2704
- 14850
- 113
- 12635
- 2662
- 27783
- 23100
- 29478
- 1175
- 29260
- 4308
- 56268
- 2368
- 46305
- 304
- 5700
- 27783
- 3116
- 9504
- 30580
- 4416
- 19456
- 52832
- 290
- 10908
- 52440
- 3372
- 1075
- 676
- 272
- 6360
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