Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹17600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹23900 at 10% per year for 2 years (in ₹)?
- 3.A scooter is worth ₹2800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 4.What amount will ₹57100 grow to in 1 year at 25% per year compound interest (in ₹)?
- 5.A town has 54400 people. The population grows by 5% every year. What will the population be after 1 year?
- 6.Find the compound interest on ₹37400 at 4% per year for 1 year, compounded every year (in ₹).
- 7.A town has 22000 people. The population grows by 5% every year. What will the population be after 2 years?
- 8.A town has 17600 people. The population grows by 20% every year. What will the population be after 1 year?
- 9.What amount will ₹2800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹57200 at 15% per year for 2 years (in ₹)?
- 11.A scooter is worth ₹49500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 12.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
- 13.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
- 14.A scooter is worth ₹43200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹25200 at 15% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹54400 at 15% per year for 2 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
- 18.Find the compound interest on ₹17700 at 20% per year for 1 year, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
- 21.What amount will ₹50000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 22.Find the compound interest on ₹18000 at 10% per year for 3 years, compounded every year (in ₹).
- 23.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 24.A scooter is worth ₹8200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 25.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹29900 at 20% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹42100 at 15% per year for 1 year, compounded every year (in ₹).
- 30.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 31.What is the difference between the compound interest and the simple interest on ₹5600 at 5% per year for 2 years (in ₹)?
- 32.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 33.What amount will ₹40400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 34.What amount will ₹10400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 35.Find the compound interest on ₹20000 at 4% per year for 1 year, compounded every year (in ₹).
- 36.What amount will ₹15100 grow to in 1 year at 10% per year compound interest (in ₹)?
- 37.What amount will ₹15700 grow to in 2 years at 10% per year compound interest (in ₹)?
- 38.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 39.A town has 54800 people. The population grows by 20% every year. What will the population be after 2 years?
- 40.What amount will ₹45500 grow to in 1 year at 5% per year compound interest (in ₹)?
Answer key
- 7425
- 239
- 2023
- 71375
- 57120
- 1496
- 24255
- 21120
- 3703
- 1287
- 47520
- 832
- 3136
- 18225
- 567
- 17544
- 19529
- 3540
- 36
- 176
- 55125
- 5958
- 2522
- 6970
- 60835
- 192
- 1986
- 5980
- 6315
- 6305
- 14
- 20577
- 48884
- 16250
- 800
- 16610
- 18997
- 32448
- 78912
- 47775
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets