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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 909 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹54500 at 20% per year for 3 years, compounded every year (in ₹).
  2. 2.What amount will ₹26800 grow to in 2 years at 25% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹34400 at 5% per year for 2 years (in ₹)?
  4. 4.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  5. 5.What amount will ₹31200 grow to in 2 years at 25% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  7. 7.What amount will ₹19800 grow to in 1 year at 10% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹17400 at 8% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹7200 at 5% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹8800 at 25% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹36400 at 25% per year for 2 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹39200 at 15% per year for 2 years (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  15. 15.A scooter is worth ₹21300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  16. 16.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹41000 at 20% per year for 3 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹52400 at 10% per year for 2 years, compounded every year (in ₹).
  20. 20.What amount will ₹11200 grow to in 2 years at 25% per year compound interest (in ₹)?
  21. 21.Find the compound interest on ₹26700 at 8% per year for 1 year, compounded every year (in ₹).
  22. 22.What amount will ₹9200 grow to in 1 year at 8% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
  24. 24.What amount will ₹9400 grow to in 2 years at 20% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  26. 26.What amount will ₹21200 grow to in 2 years at 5% per year compound interest (in ₹)?
  27. 27.What amount will ₹19600 grow to in 2 years at 5% per year compound interest (in ₹)?
  28. 28.Find the compound interest on ₹14700 at 8% per year for 1 year, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  30. 30.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹27200 at 25% per year for 2 years (in ₹)?
  32. 32.A scooter is worth ₹27500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  33. 33.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹18800 at 20% per year for 1 year, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹50800 at 10% per year for 2 years (in ₹)?
  36. 36.What amount will ₹7400 grow to in 1 year at 5% per year compound interest (in ₹)?
  37. 37.A town has 42500 people. The population grows by 12% every year. What will the population be after 2 years?
  38. 38.Find the compound interest on ₹8100 at 25% per year for 1 year, compounded every year (in ₹).
  39. 39.What amount will ₹9900 grow to in 2 years at 10% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹7600 at 10% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 39676
  2. 41875
  3. 86
  4. 18522
  5. 48750
  6. 1261
  7. 21780
  8. 1392
  9. 8748
  10. 18
  11. 550
  12. 20475
  13. 882
  14. 864
  15. 20235
  16. 54571
  17. 176
  18. 29848
  19. 11004
  20. 17500
  21. 2136
  22. 9936
  23. 408
  24. 13536
  25. 34295
  26. 23373
  27. 21609
  28. 1176
  29. 6305
  30. 27436
  31. 1700
  32. 23276
  33. 85169
  34. 3760
  35. 508
  36. 7770
  37. 53312
  38. 2025
  39. 11979
  40. 1596

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