Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 910 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹35300 at 15% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹24200 at 10% per year for 2 years, compounded every year (in ₹).
5. 5.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹6400 at 15% per year for 2 years (in ₹)?
9. 9.A town has 9600 people. The population grows by 15% every year. What will the population be after 2 years?
10. 10.A scooter is worth ₹38700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
11. 11.A town has 42800 people. The population grows by 15% every year. What will the population be after 2 years?
12. 12.Find the compound interest on ₹54800 at 4% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹35300 at 10% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹44400 grow to in 1 year at 10% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹32000 at 4% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹48000 grow to in 3 years at 25% per year compound interest (in ₹)?
17. 17.A town has 54400 people. The population grows by 25% every year. What will the population be after 1 year?
18. 18.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹1600 at 25% per year for 3 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹18700 at 15% per year for 1 year, compounded every year (in ₹).
21. 21.Find the compound interest on ₹14000 at 25% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹3200 at 8% per year for 1 year, compounded every year (in ₹).
23. 23.Find the compound interest on ₹48900 at 10% per year for 2 years, compounded every year (in ₹).
24. 24.A town has 29000 people. The population grows by 10% every year. What will the population be after 2 years?
25. 25.Find the compound interest on ₹22000 at 10% per year for 3 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹42400 at 15% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹14800 at 25% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹54000 grow to in 1 year at 10% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹47000 grow to in 3 years at 20% per year compound interest (in ₹)?
33. 33.What amount will ₹37100 grow to in 2 years at 10% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹4400 at 15% per year for 2 years (in ₹)?
35. 35.A town has 54000 people. The population grows by 10% every year. What will the population be after 3 years?
36. 36.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹47200 at 8% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
39. 39.What amount will ₹52200 grow to in 1 year at 4% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹3600 at 8% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets