Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 911 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹11200 at 15% per year for 2 years (in ₹)?
3. 3.A town has 53100 people. The population grows by 4% every year. What will the population be after 1 year?
4. 4.A town has 41200 people. The population grows by 25% every year. What will the population be after 2 years?
5. 5.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
6. 6.What amount will ₹37700 grow to in 1 year at 4% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹39200 at 5% per year for 2 years (in ₹)?
8. 8.A town has 58000 people. The population grows by 25% every year. What will the population be after 2 years?
9. 9.A town has 5200 people. The population grows by 5% every year. What will the population be after 1 year?
10. 10.What amount will ₹57800 grow to in 1 year at 20% per year compound interest (in ₹)?
11. 11.What amount will ₹19200 grow to in 2 years at 20% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹29600 at 15% per year for 2 years (in ₹)?
13. 13.What amount will ₹50800 grow to in 1 year at 20% per year compound interest (in ₹)?
14. 14.A town has 54000 people. The population grows by 5% every year. What will the population be after 1 year?
15. 15.What amount will ₹6800 grow to in 2 years at 20% per year compound interest (in ₹)?
16. 16.A town has 28900 people. The population grows by 10% every year. What will the population be after 2 years?
17. 17.Find the compound interest on ₹14300 at 20% per year for 1 year, compounded every year (in ₹).
18. 18.A scooter is worth ₹3400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹42800 at 5% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹52000 at 20% per year for 3 years, compounded every year (in ₹).
22. 22.A scooter is worth ₹3600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
23. 23.A scooter is worth ₹28700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
24. 24.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹35700 at 25% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹15200 at 15% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹53000 grow to in 1 year at 15% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹39400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
29. 29.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹18000 at 15% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
32. 32.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
33. 33.A scooter is worth ₹17600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
34. 34.Find the compound interest on ₹42400 at 20% per year for 1 year, compounded every year (in ₹).
35. 35.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
36. 36.A scooter is worth ₹24800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹6800 at 5% per year for 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹4500 at 15% per year for 1 year, compounded every year (in ₹).

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