Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 912 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
2. 2.A town has 43800 people. The population grows by 20% every year. What will the population be after 1 year?
3. 3.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹28000 at 10% per year for 3 years, compounded every year (in ₹).
5. 5.A town has 52500 people. The population grows by 4% every year. What will the population be after 2 years?
6. 6.Find the compound interest on ₹45000 at 8% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹55400 grow to in 1 year at 10% per year compound interest (in ₹)?
8. 8.A town has 56200 people. The population grows by 10% every year. What will the population be after 1 year?
9. 9.A town has 22600 people. The population grows by 8% every year. What will the population be after 1 year?
10. 10.What amount will ₹54200 grow to in 1 year at 5% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹22400 at 12% per year for 1 year, compounded every year (in ₹).
13. 13.A town has 9700 people. The population grows by 15% every year. What will the population be after 1 year?
14. 14.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹49100 at 10% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹30500 grow to in 2 years at 10% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹12000 at 15% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
19. 19.A town has 47400 people. The population grows by 15% every year. What will the population be after 1 year?
20. 20.What amount will ₹17600 grow to in 2 years at 10% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹33500 at 20% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹6000 at 15% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹15600 at 25% per year for 2 years (in ₹)?
24. 24.A town has 26000 people. The population grows by 10% every year. What will the population be after 3 years?
25. 25.Find the compound interest on ₹52900 at 25% per year for 1 year, compounded every year (in ₹).
26. 26.A town has 6300 people. The population grows by 25% every year. What will the population be after 1 year?
27. 27.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
28. 28.Find the compound interest on ₹3600 at 5% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹4200 at 20% per year for 2 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹40000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹51200 at 25% per year for 3 years, compounded every year (in ₹).
34. 34.A scooter is worth ₹29000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
35. 35.A town has 10800 people. The population grows by 20% every year. What will the population be after 1 year?
36. 36.What is the difference between the compound interest and the simple interest on ₹48400 at 25% per year for 2 years (in ₹)?
37. 37.What amount will ₹11500 grow to in 3 years at 20% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹30700 at 4% per year for 1 year, compounded every year (in ₹).
39. 39.A scooter is worth ₹28200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
40. 40.What amount will ₹46600 grow to in 1 year at 12% per year compound interest (in ₹)?

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