Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 918 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹19000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹42000 at 25% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹34400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹45000 at 10% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
7. 7.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
8. 8.What amount will ₹35500 grow to in 3 years at 20% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹10300 at 10% per year for 2 years, compounded every year (in ₹).
10. 10.What amount will ₹31200 grow to in 2 years at 10% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹8900 grow to in 1 year at 15% per year compound interest (in ₹)?
13. 13.A town has 8200 people. The population grows by 15% every year. What will the population be after 1 year?
14. 14.What is the difference between the compound interest and the simple interest on ₹59500 at 20% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹36000 at 15% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹52300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
17. 17.Find the compound interest on ₹6000 at 20% per year for 3 years, compounded every year (in ₹).
18. 18.What amount will ₹8700 grow to in 1 year at 4% per year compound interest (in ₹)?
19. 19.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
20. 20.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹42400 at 25% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹37200 at 15% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹7900 at 10% per year for 2 years, compounded every year (in ₹).
26. 26.A town has 41700 people. The population grows by 20% every year. What will the population be after 2 years?
27. 27.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹7500 at 20% per year for 2 years (in ₹)?
29. 29.What amount will ₹2100 grow to in 2 years at 20% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹17600 at 5% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹29900 grow to in 1 year at 20% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹34200 at 10% per year for 2 years (in ₹)?
33. 33.What amount will ₹24000 grow to in 3 years at 20% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
35. 35.A town has 31100 people. The population grows by 10% every year. What will the population be after 1 year?
36. 36.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹17000 at 15% per year for 1 year, compounded every year (in ₹).
38. 38.A scooter is worth ₹40000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
40. 40.A scooter is worth ₹45000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?

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