Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 923 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 35600 people. The population grows by 10% every year. What will the population be after 2 years?
2. 2.Find the compound interest on ₹32400 at 5% per year for 1 year, compounded every year (in ₹).
3. 3.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
4. 4.Find the compound interest on ₹32200 at 8% per year for 1 year, compounded every year (in ₹).
5. 5.What amount will ₹30000 grow to in 2 years at 15% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹48700 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹21000 at 10% per year for 3 years, compounded every year (in ₹).
8. 8.A town has 42500 people. The population grows by 12% every year. What will the population be after 2 years?
9. 9.What amount will ₹46700 grow to in 1 year at 8% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹48500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
11. 11.A town has 14400 people. The population grows by 25% every year. What will the population be after 3 years?
12. 12.A scooter is worth ₹23100. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
13. 13.What amount will ₹31500 grow to in 1 year at 5% per year compound interest (in ₹)?
14. 14.A town has 14500 people. The population grows by 10% every year. What will the population be after 1 year?
15. 15.What amount will ₹48600 grow to in 1 year at 10% per year compound interest (in ₹)?
16. 16.A scooter is worth ₹43500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
17. 17.Find the compound interest on ₹17200 at 15% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹18000 at 20% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
22. 22.A scooter is worth ₹56300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
23. 23.What amount will ₹50300 grow to in 1 year at 25% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹46000 at 10% per year for 3 years, compounded every year (in ₹).
25. 25.What amount will ₹53000 grow to in 3 years at 10% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹28400 at 5% per year for 2 years (in ₹)?
28. 28.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹13100 at 12% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
32. 32.A scooter is worth ₹55200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
34. 34.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹36400 at 25% per year for 2 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹17500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
37. 37.Find the compound interest on ₹42600 at 10% per year for 1 year, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹7600 at 10% per year for 2 years (in ₹)?
39. 39.What amount will ₹39000 grow to in 3 years at 20% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹44300 at 10% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets