Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 93 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹6000 at 5% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
5. 5.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹51200 at 12% per year for 1 year, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
9. 9.A town has 15900 people. The population grows by 4% every year. What will the population be after 1 year?
10. 10.What amount will ₹58000 grow to in 3 years at 20% per year compound interest (in ₹)?
11. 11.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
12. 12.A town has 14000 people. The population grows by 10% every year. What will the population be after 3 years?
13. 13.What is the difference between the compound interest and the simple interest on ₹22000 at 25% per year for 2 years (in ₹)?
14. 14.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹22100 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
17. 17.What amount will ₹36000 grow to in 3 years at 20% per year compound interest (in ₹)?
18. 18.What amount will ₹3100 grow to in 1 year at 5% per year compound interest (in ₹)?
19. 19.What amount will ₹38800 grow to in 2 years at 5% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹42800 at 15% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹24100 at 20% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹54900 at 10% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹54700 at 20% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹44000 grow to in 3 years at 10% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹17500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
26. 26.A scooter is worth ₹41100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
27. 27.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹11600 at 25% per year for 2 years, compounded every year (in ₹).
29. 29.A town has 14500 people. The population grows by 25% every year. What will the population be after 1 year?
30. 30.A scooter is worth ₹54400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
31. 31.Find the compound interest on ₹9400 at 10% per year for 1 year, compounded every year (in ₹).
32. 32.What amount will ₹2600 grow to in 1 year at 5% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹25100 at 10% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹2800 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹7700 grow to in 1 year at 8% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹22400 at 25% per year for 2 years (in ₹)?
38. 38.A town has 57900 people. The population grows by 4% every year. What will the population be after 1 year?
39. 39.What amount will ₹42700 grow to in 2 years at 10% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹37400 at 10% per year for 2 years, compounded every year (in ₹).

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