Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 8200 people. The population grows by 5% every year. What will the population be after 1 year?
- 2.Find the compound interest on ₹22500 at 20% per year for 1 year, compounded every year (in ₹).
- 3.What is the difference between the compound interest and the simple interest on ₹30400 at 25% per year for 2 years (in ₹)?
- 4.What amount will ₹55000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 5.Find the compound interest on ₹48700 at 5% per year for 1 year, compounded every year (in ₹).
- 6.A scooter is worth ₹27300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 7.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
- 8.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 9.A town has 28400 people. The population grows by 10% every year. What will the population be after 2 years?
- 10.A scooter is worth ₹10800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 11.A town has 52600 people. The population grows by 15% every year. What will the population be after 1 year?
- 12.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
- 13.What amount will ₹16000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹38000 at 20% per year for 3 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
- 17.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 18.A scooter is worth ₹12400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 19.A town has 23000 people. The population grows by 8% every year. What will the population be after 1 year?
- 20.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
- 21.A town has 28400 people. The population grows by 12% every year. What will the population be after 1 year?
- 22.Find the compound interest on ₹27100 at 12% per year for 1 year, compounded every year (in ₹).
- 23.What amount will ₹37500 grow to in 1 year at 8% per year compound interest (in ₹)?
- 24.A scooter is worth ₹35100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 25.Find the compound interest on ₹44400 at 20% per year for 1 year, compounded every year (in ₹).
- 26.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹38900 at 12% per year for 1 year, compounded every year (in ₹).
- 28.Find the compound interest on ₹56500 at 20% per year for 3 years, compounded every year (in ₹).
- 29.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 30.A town has 32000 people. The population grows by 5% every year. What will the population be after 1 year?
- 31.What amount will ₹40100 grow to in 1 year at 4% per year compound interest (in ₹)?
- 32.Find the compound interest on ₹27800 at 20% per year for 2 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹4000 at 5% per year for 2 years, compounded every year (in ₹).
- 34.A town has 52500 people. The population grows by 12% every year. What will the population be after 2 years?
- 35.What amount will ₹44700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 36.A town has 40600 people. The population grows by 15% every year. What will the population be after 1 year?
- 37.A town has 6200 people. The population grows by 5% every year. What will the population be after 1 year?
- 38.A scooter is worth ₹54100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
- 40.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
Answer key
- 8610
- 4500
- 1900
- 64152
- 2435
- 22113
- 2912
- 64827
- 34364
- 6075
- 60490
- 384
- 21160
- 27664
- 30
- 96
- 13718
- 11160
- 24840
- 55566
- 31808
- 3252
- 40500
- 28431
- 8880
- 33550
- 4668
- 41132
- 15972
- 33600
- 41704
- 12232
- 410
- 65856
- 49170
- 46690
- 6510
- 51395
- 64
- 65856
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