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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 931 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 8200 people. The population grows by 5% every year. What will the population be after 1 year?
  2. 2.Find the compound interest on ₹22500 at 20% per year for 1 year, compounded every year (in ₹).
  3. 3.What is the difference between the compound interest and the simple interest on ₹30400 at 25% per year for 2 years (in ₹)?
  4. 4.What amount will ₹55000 grow to in 2 years at 8% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹48700 at 5% per year for 1 year, compounded every year (in ₹).
  6. 6.A scooter is worth ₹27300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  7. 7.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
  8. 8.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  9. 9.A town has 28400 people. The population grows by 10% every year. What will the population be after 2 years?
  10. 10.A scooter is worth ₹10800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  11. 11.A town has 52600 people. The population grows by 15% every year. What will the population be after 1 year?
  12. 12.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  13. 13.What amount will ₹16000 grow to in 2 years at 15% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹38000 at 20% per year for 3 years, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  17. 17.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  18. 18.A scooter is worth ₹12400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  19. 19.A town has 23000 people. The population grows by 8% every year. What will the population be after 1 year?
  20. 20.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  21. 21.A town has 28400 people. The population grows by 12% every year. What will the population be after 1 year?
  22. 22.Find the compound interest on ₹27100 at 12% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹37500 grow to in 1 year at 8% per year compound interest (in ₹)?
  24. 24.A scooter is worth ₹35100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  25. 25.Find the compound interest on ₹44400 at 20% per year for 1 year, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹38900 at 12% per year for 1 year, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹56500 at 20% per year for 3 years, compounded every year (in ₹).
  29. 29.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
  30. 30.A town has 32000 people. The population grows by 5% every year. What will the population be after 1 year?
  31. 31.What amount will ₹40100 grow to in 1 year at 4% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹27800 at 20% per year for 2 years, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹4000 at 5% per year for 2 years, compounded every year (in ₹).
  34. 34.A town has 52500 people. The population grows by 12% every year. What will the population be after 2 years?
  35. 35.What amount will ₹44700 grow to in 1 year at 10% per year compound interest (in ₹)?
  36. 36.A town has 40600 people. The population grows by 15% every year. What will the population be after 1 year?
  37. 37.A town has 6200 people. The population grows by 5% every year. What will the population be after 1 year?
  38. 38.A scooter is worth ₹54100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
  40. 40.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?

Answer key

  1. 8610
  2. 4500
  3. 1900
  4. 64152
  5. 2435
  6. 22113
  7. 2912
  8. 64827
  9. 34364
  10. 6075
  11. 60490
  12. 384
  13. 21160
  14. 27664
  15. 30
  16. 96
  17. 13718
  18. 11160
  19. 24840
  20. 55566
  21. 31808
  22. 3252
  23. 40500
  24. 28431
  25. 8880
  26. 33550
  27. 4668
  28. 41132
  29. 15972
  30. 33600
  31. 41704
  32. 12232
  33. 410
  34. 65856
  35. 49170
  36. 46690
  37. 6510
  38. 51395
  39. 64
  40. 65856

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