Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 937 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 22800 people. The population grows by 20% every year. What will the population be after 2 years?
2. 2.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹57600 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹45000 at 20% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
6. 6.A town has 13600 people. The population grows by 12% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹44800 at 10% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹4000 grow to in 2 years at 5% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹40800 at 25% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹29000 at 10% per year for 3 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
12. 12.A town has 58000 people. The population grows by 15% every year. What will the population be after 2 years?
13. 13.A scooter is worth ₹42600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
14. 14.Find the compound interest on ₹55600 at 15% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹50900 at 20% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
18. 18.What amount will ₹41200 grow to in 2 years at 15% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹59000 at 20% per year for 3 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹34900 at 20% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹18400 at 25% per year for 2 years (in ₹)?
22. 22.What amount will ₹48000 grow to in 3 years at 25% per year compound interest (in ₹)?
23. 23.A town has 41600 people. The population grows by 25% every year. What will the population be after 3 years?
24. 24.What amount will ₹14100 grow to in 2 years at 20% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹51400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
26. 26.Find the compound interest on ₹40900 at 4% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹45800 grow to in 1 year at 15% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹40600 at 10% per year for 2 years (in ₹)?
29. 29.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
30. 30.A scooter is worth ₹18700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹41600 at 15% per year for 2 years (in ₹)?
32. 32.What amount will ₹8700 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹37600 at 5% per year for 2 years (in ₹)?
34. 34.What amount will ₹16000 grow to in 2 years at 25% per year compound interest (in ₹)?
35. 35.What amount will ₹50900 grow to in 2 years at 10% per year compound interest (in ₹)?
36. 36.What amount will ₹22500 grow to in 1 year at 12% per year compound interest (in ₹)?
37. 37.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
38. 38.Find the compound interest on ₹30000 at 20% per year for 1 year, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?

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