← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 938 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A town has 16400 people. The population grows by 25% every year. What will the population be after 2 years?
  2. 2.A town has 57700 people. The population grows by 10% every year. What will the population be after 1 year?
  3. 3.What amount will ₹17200 grow to in 1 year at 10% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹24000 at 10% per year for 1 year, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹49200 at 12% per year for 1 year, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹49600 at 5% per year for 2 years (in ₹)?
  8. 8.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹5800 at 20% per year for 1 year, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹10400 at 25% per year for 2 years, compounded every year (in ₹).
  13. 13.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹43500 at 4% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹42400 at 25% per year for 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹35600 at 25% per year for 2 years (in ₹)?
  18. 18.A town has 4100 people. The population grows by 20% every year. What will the population be after 2 years?
  19. 19.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
  20. 20.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
  21. 21.What amount will ₹17600 grow to in 2 years at 25% per year compound interest (in ₹)?
  22. 22.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  23. 23.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  24. 24.What amount will ₹56400 grow to in 2 years at 15% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹13100 at 15% per year for 1 year, compounded every year (in ₹).
  26. 26.What amount will ₹5000 grow to in 1 year at 20% per year compound interest (in ₹)?
  27. 27.A scooter is worth ₹57500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  28. 28.What amount will ₹42800 grow to in 2 years at 25% per year compound interest (in ₹)?
  29. 29.What amount will ₹58900 grow to in 1 year at 12% per year compound interest (in ₹)?
  30. 30.What amount will ₹12600 grow to in 1 year at 8% per year compound interest (in ₹)?
  31. 31.A scooter is worth ₹6300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  32. 32.Find the compound interest on ₹35500 at 15% per year for 1 year, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹36500 at 20% per year for 3 years, compounded every year (in ₹).
  34. 34.A scooter is worth ₹18000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  35. 35.What amount will ₹8300 grow to in 2 years at 10% per year compound interest (in ₹)?
  36. 36.A town has 12400 people. The population grows by 15% every year. What will the population be after 2 years?
  37. 37.What is the difference between the compound interest and the simple interest on ₹26500 at 20% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  39. 39.What amount will ₹23200 grow to in 1 year at 12% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹59900 at 10% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 25625
  2. 63470
  3. 18920
  4. 224
  5. 2400
  6. 5904
  7. 124
  8. 10816
  9. 1160
  10. 10675
  11. 3060
  12. 5850
  13. 23328
  14. 1740
  15. 3783
  16. 2650
  17. 2225
  18. 5904
  19. 51850
  20. 37500
  21. 27500
  22. 5776
  23. 7744
  24. 74589
  25. 1965
  26. 6000
  27. 54625
  28. 66875
  29. 65968
  30. 13608
  31. 5670
  32. 5325
  33. 26572
  34. 16245
  35. 10043
  36. 16399
  37. 1060
  38. 5044
  39. 25984
  40. 5990

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets