Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 16400 people. The population grows by 25% every year. What will the population be after 2 years?
- 2.A town has 57700 people. The population grows by 10% every year. What will the population be after 1 year?
- 3.What amount will ₹17200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹24000 at 10% per year for 1 year, compounded every year (in ₹).
- 6.Find the compound interest on ₹49200 at 12% per year for 1 year, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹49600 at 5% per year for 2 years (in ₹)?
- 8.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹5800 at 20% per year for 1 year, compounded every year (in ₹).
- 10.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹10400 at 25% per year for 2 years, compounded every year (in ₹).
- 13.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹43500 at 4% per year for 1 year, compounded every year (in ₹).
- 15.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹42400 at 25% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹35600 at 25% per year for 2 years (in ₹)?
- 18.A town has 4100 people. The population grows by 20% every year. What will the population be after 2 years?
- 19.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
- 20.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 21.What amount will ₹17600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 22.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 23.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 24.What amount will ₹56400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 25.Find the compound interest on ₹13100 at 15% per year for 1 year, compounded every year (in ₹).
- 26.What amount will ₹5000 grow to in 1 year at 20% per year compound interest (in ₹)?
- 27.A scooter is worth ₹57500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 28.What amount will ₹42800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 29.What amount will ₹58900 grow to in 1 year at 12% per year compound interest (in ₹)?
- 30.What amount will ₹12600 grow to in 1 year at 8% per year compound interest (in ₹)?
- 31.A scooter is worth ₹6300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 32.Find the compound interest on ₹35500 at 15% per year for 1 year, compounded every year (in ₹).
- 33.Find the compound interest on ₹36500 at 20% per year for 3 years, compounded every year (in ₹).
- 34.A scooter is worth ₹18000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 35.What amount will ₹8300 grow to in 2 years at 10% per year compound interest (in ₹)?
- 36.A town has 12400 people. The population grows by 15% every year. What will the population be after 2 years?
- 37.What is the difference between the compound interest and the simple interest on ₹26500 at 20% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 39.What amount will ₹23200 grow to in 1 year at 12% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹59900 at 10% per year for 1 year, compounded every year (in ₹).
Answer key
- 25625
- 63470
- 18920
- 224
- 2400
- 5904
- 124
- 10816
- 1160
- 10675
- 3060
- 5850
- 23328
- 1740
- 3783
- 2650
- 2225
- 5904
- 51850
- 37500
- 27500
- 5776
- 7744
- 74589
- 1965
- 6000
- 54625
- 66875
- 65968
- 13608
- 5670
- 5325
- 26572
- 16245
- 10043
- 16399
- 1060
- 5044
- 25984
- 5990
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