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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 939 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 17300 people. The population grows by 20% every year. What will the population be after 2 years?
  2. 2.What amount will ₹3300 grow to in 1 year at 8% per year compound interest (in ₹)?
  3. 3.A town has 9600 people. The population grows by 25% every year. What will the population be after 2 years?
  4. 4.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹38500 at 4% per year for 1 year, compounded every year (in ₹).
  6. 6.What amount will ₹35800 grow to in 1 year at 4% per year compound interest (in ₹)?
  7. 7.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
  8. 8.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
  9. 9.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹50800 at 5% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹57600 at 25% per year for 3 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹53700 at 20% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹42000 at 5% per year for 2 years, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹52800 at 12% per year for 1 year, compounded every year (in ₹).
  16. 16.What amount will ₹51200 grow to in 1 year at 5% per year compound interest (in ₹)?
  17. 17.A town has 31600 people. The population grows by 25% every year. What will the population be after 2 years?
  18. 18.A town has 28800 people. The population grows by 25% every year. What will the population be after 3 years?
  19. 19.Find the compound interest on ₹26900 at 4% per year for 1 year, compounded every year (in ₹).
  20. 20.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
  21. 21.What amount will ₹31900 grow to in 1 year at 8% per year compound interest (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹36800 at 15% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹2000 at 15% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹7900 at 20% per year for 1 year, compounded every year (in ₹).
  25. 25.What amount will ₹6400 grow to in 1 year at 15% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹13000 at 10% per year for 2 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹47700 at 5% per year for 1 year, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹56200 at 10% per year for 2 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹21200 at 10% per year for 1 year, compounded every year (in ₹).
  30. 30.What amount will ₹6000 grow to in 1 year at 10% per year compound interest (in ₹)?
  31. 31.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
  32. 32.A town has 14200 people. The population grows by 15% every year. What will the population be after 1 year?
  33. 33.A town has 32000 people. The population grows by 25% every year. What will the population be after 3 years?
  34. 34.What is the difference between the compound interest and the simple interest on ₹29200 at 5% per year for 2 years (in ₹)?
  35. 35.Find the compound interest on ₹12800 at 15% per year for 2 years, compounded every year (in ₹).
  36. 36.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  37. 37.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  38. 38.What amount will ₹14000 grow to in 3 years at 20% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹47600 at 20% per year for 1 year, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?

Answer key

  1. 24912
  2. 3564
  3. 15000
  4. 60835
  5. 1540
  6. 37232
  7. 73002
  8. 8736
  9. 43904
  10. 127
  11. 468
  12. 54900
  13. 2148
  14. 4305
  15. 6336
  16. 53760
  17. 49375
  18. 56250
  19. 1076
  20. 43740
  21. 34452
  22. 828
  23. 645
  24. 1580
  25. 7360
  26. 2730
  27. 2385
  28. 11802
  29. 2120
  30. 6600
  31. 14580
  32. 16330
  33. 62500
  34. 73
  35. 4128
  36. 9261
  37. 1261
  38. 24192
  39. 9520
  40. 12

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