Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 96 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹10800 at 15% per year for 2 years (in ₹)?
2. 2.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
3. 3.A town has 16500 people. The population grows by 5% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹19600 at 5% per year for 2 years, compounded every year (in ₹).
5. 5.What amount will ₹45600 grow to in 2 years at 5% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹44000 at 10% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹58800 at 5% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹9000 at 25% per year for 1 year, compounded every year (in ₹).
11. 11.A town has 32500 people. The population grows by 20% every year. What will the population be after 3 years?
12. 12.Find the compound interest on ₹50800 at 5% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹39200 grow to in 2 years at 5% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹14700 at 20% per year for 1 year, compounded every year (in ₹).
18. 18.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹11200 at 15% per year for 2 years (in ₹)?
20. 20.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹32600 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹7400 at 10% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹9900 at 5% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹42000 grow to in 2 years at 15% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹47500 at 5% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹26000 at 25% per year for 2 years, compounded every year (in ₹).
30. 30.A town has 13400 people. The population grows by 20% every year. What will the population be after 2 years?
31. 31.What is the difference between the compound interest and the simple interest on ₹47200 at 10% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹46800 at 5% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹40000 at 25% per year for 3 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹24400 at 25% per year for 2 years (in ₹)?
35. 35.A town has 42000 people. The population grows by 15% every year. What will the population be after 2 years?
36. 36.A town has 25000 people. The population grows by 20% every year. What will the population be after 3 years?
37. 37.Find the compound interest on ₹38200 at 25% per year for 1 year, compounded every year (in ₹).
38. 38.What amount will ₹13200 grow to in 2 years at 10% per year compound interest (in ₹)?
39. 39.A scooter is worth ₹44500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?

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