Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 97 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹56900 at 4% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹47500 at 20% per year for 3 years, compounded every year (in ₹).
3. 3.A town has 27300 people. The population grows by 10% every year. What will the population be after 2 years?
4. 4.A town has 16400 people. The population grows by 5% every year. What will the population be after 2 years?
5. 5.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
6. 6.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
7. 7.Find the compound interest on ₹8900 at 12% per year for 1 year, compounded every year (in ₹).
8. 8.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹4800 at 12% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹57100 at 20% per year for 2 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹48000 at 25% per year for 3 years, compounded every year (in ₹).
14. 14.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
15. 15.Find the compound interest on ₹57600 at 15% per year for 2 years, compounded every year (in ₹).
16. 16.A town has 17500 people. The population grows by 20% every year. What will the population be after 1 year?
17. 17.Find the compound interest on ₹50400 at 10% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
19. 19.What amount will ₹41000 grow to in 1 year at 20% per year compound interest (in ₹)?
20. 20.What amount will ₹9100 grow to in 1 year at 5% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹9800 at 25% per year for 1 year, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹32400 at 10% per year for 2 years (in ₹)?
23. 23.What amount will ₹55200 grow to in 2 years at 25% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹11200 at 25% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
27. 27.What amount will ₹58400 grow to in 2 years at 5% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹22800 at 25% per year for 2 years (in ₹)?
29. 29.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
30. 30.What amount will ₹55000 grow to in 3 years at 10% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹10800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
32. 32.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
33. 33.What amount will ₹13200 grow to in 2 years at 20% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹33600 at 20% per year for 1 year, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹38000 at 25% per year for 2 years, compounded every year (in ₹).
38. 38.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹31000 at 10% per year for 3 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).

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