Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹36300 at 10% per year for 2 years (in ₹)?
- 2.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 3.What amount will ₹14400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹42000 at 20% per year for 2 years (in ₹)?
- 5.What amount will ₹23400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 6.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 7.What amount will ₹32000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 9.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
- 10.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
- 11.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹16400 at 10% per year for 2 years (in ₹)?
- 14.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 15.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹16000 at 5% per year for 2 years, compounded every year (in ₹).
- 18.What is the difference between the compound interest and the simple interest on ₹28800 at 5% per year for 2 years (in ₹)?
- 19.A scooter is worth ₹31000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 20.What amount will ₹44400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 21.A scooter is worth ₹25000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 22.A scooter is worth ₹48900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 23.A town has 49200 people. The population grows by 25% every year. What will the population be after 2 years?
- 24.Find the compound interest on ₹46000 at 20% per year for 3 years, compounded every year (in ₹).
- 25.What amount will ₹49300 grow to in 1 year at 25% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
- 27.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 28.What amount will ₹33600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹23900 at 20% per year for 1 year, compounded every year (in ₹).
- 30.What amount will ₹55000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹48000 at 20% per year for 2 years (in ₹)?
- 32.What amount will ₹36900 grow to in 1 year at 10% per year compound interest (in ₹)?
- 33.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 34.A town has 48200 people. The population grows by 15% every year. What will the population be after 1 year?
- 35.What amount will ₹6800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹51500 at 15% per year for 1 year, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
- 40.A town has 5000 people. The population grows by 10% every year. What will the population be after 3 years?
Answer key
- 363
- 4167
- 15876
- 1680
- 28314
- 14641
- 42592
- 8334
- 160
- 46305
- 60835
- 360
- 164
- 65856
- 12500
- 17212
- 1640
- 72
- 22599
- 58719
- 19360
- 39120
- 76875
- 33488
- 61625
- 10675
- 19200
- 34944
- 4780
- 64152
- 1920
- 40590
- 20577
- 55430
- 7480
- 7725
- 80
- 84
- 29169
- 6655
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets