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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 963 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹36300 at 10% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  3. 3.What amount will ₹14400 grow to in 2 years at 5% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹42000 at 20% per year for 2 years (in ₹)?
  5. 5.What amount will ₹23400 grow to in 2 years at 10% per year compound interest (in ₹)?
  6. 6.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
  7. 7.What amount will ₹32000 grow to in 3 years at 10% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
  10. 10.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
  11. 11.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹16400 at 10% per year for 2 years (in ₹)?
  14. 14.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
  15. 15.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹16000 at 5% per year for 2 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹28800 at 5% per year for 2 years (in ₹)?
  19. 19.A scooter is worth ₹31000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  20. 20.What amount will ₹44400 grow to in 2 years at 15% per year compound interest (in ₹)?
  21. 21.A scooter is worth ₹25000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  22. 22.A scooter is worth ₹48900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  23. 23.A town has 49200 people. The population grows by 25% every year. What will the population be after 2 years?
  24. 24.Find the compound interest on ₹46000 at 20% per year for 3 years, compounded every year (in ₹).
  25. 25.What amount will ₹49300 grow to in 1 year at 25% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  27. 27.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  28. 28.What amount will ₹33600 grow to in 1 year at 4% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹23900 at 20% per year for 1 year, compounded every year (in ₹).
  30. 30.What amount will ₹55000 grow to in 2 years at 8% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹48000 at 20% per year for 2 years (in ₹)?
  32. 32.What amount will ₹36900 grow to in 1 year at 10% per year compound interest (in ₹)?
  33. 33.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  34. 34.A town has 48200 people. The population grows by 15% every year. What will the population be after 1 year?
  35. 35.What amount will ₹6800 grow to in 1 year at 10% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹51500 at 15% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  40. 40.A town has 5000 people. The population grows by 10% every year. What will the population be after 3 years?

Answer key

  1. 363
  2. 4167
  3. 15876
  4. 1680
  5. 28314
  6. 14641
  7. 42592
  8. 8334
  9. 160
  10. 46305
  11. 60835
  12. 360
  13. 164
  14. 65856
  15. 12500
  16. 17212
  17. 1640
  18. 72
  19. 22599
  20. 58719
  21. 19360
  22. 39120
  23. 76875
  24. 33488
  25. 61625
  26. 10675
  27. 19200
  28. 34944
  29. 4780
  30. 64152
  31. 1920
  32. 40590
  33. 20577
  34. 55430
  35. 7480
  36. 7725
  37. 80
  38. 84
  39. 29169
  40. 6655

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